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statuscvo [17]
3 years ago
8

PLEASE ANSWER FOR 15 POINTS!!

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
4 0
The amount of paint required to paint the whole cupboard is:

https://tex.z-dn.net/?f=2%5Ctimes2.5%5E2%2B4%5Ctimes%282.5%5Ctimes3.5%29%0A%5C%5C%3D47.5+++ft%5E2

The amount of paint required to paint all but the bottom surface is:

https://tex.z-dn.net/?f=2.5%5E2+%2B+4%282.5%5Ctimes3.5%29%0A%5C%5C%3D+41.25+ft%5E2

So the difference in paint required is 6.25 square feet worth of paint.
You might be interested in
I need help on these 2 questions. Algebra 1
hammer [34]

Answer:

7. is G

8. f(4)=-120

Step-by-step explanation:

7. les do f(0)=4 since its the easiest

F. f(0)=0.4(0+5)(0-2)

    0.4*-2*5=-4                NOT IT. the ans. is +

G. f(0)=-0.4(0+5)(0-2)

    -0.4*-2*5=4               YESSSSSS

H. f(0)=-0.4(0-5)(0+2)

     -0.4*2*-5=4              YESSSSSS

J. f(0)=0.4(0-5)(0+2)

     0.4*2*-5=-4              NOT ITTTT

so G n H

 Put both equation=0

G. 0=-0.4(x+5)(x-2)

    x=-5,2     YASSSS this is the ans.

4 0
3 years ago
. Duke's photography pays $9 for a 5x7 photograph.
g100num [7]

Answer:

the markup percentage is 66.67%

Step-by-step explanation:

The computation of the percent of markup based on cost is shown below:

= (Selling price - paid price) ÷ (paid price)

= ($15 - $9) ÷ ($9)

= 66.67%

By taking the difference of the selling price & paid price and then divided it by paid price we can get the percentage of markup

Hence, the markup percentage is 66.67%

5 0
2 years ago
Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0
andreev551 [17]

Recall the angle sum identity for cosine:

cos(<em>x</em> + <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

cos(<em>x</em> - <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) + sin(<em>x</em>) sin(<em>y</em>)

==>   sin(<em>x</em>) sin(<em>y</em>) = 1/2 (cos(<em>x</em> - <em>y</em>) - cos(<em>x</em> + <em>y</em>))

Then rewrite the equation as

sin(4<em>x</em>) sin(5<em>x</em>) + sin(4<em>x</em>) sin(3<em>x</em>) - sin(2<em>x</em>) sin(<em>x</em>) = 0

1/2 (cos(-<em>x</em>) - cos(9<em>x</em>)) + 1/2 (cos(<em>x</em>) - cos(7<em>x</em>)) - 1/2 (cos(<em>x</em>) - cos(3<em>x</em>)) = 0

1/2 (cos(9<em>x</em>) - cos(<em>x</em>)) + 1/2 (cos(7<em>x</em>) - cos(3<em>x</em>)) = 0

sin(5<em>x</em>) sin(-4<em>x</em>) + sin(5<em>x</em>) sin(-2<em>x</em>) = 0

-sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Rewrite the equation again as

sin(5<em>x</em>) (2 sin(2<em>x</em>) cos(2<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) sin(2<em>x</em>) (2 cos(2<em>x</em>) + 1) = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   2 cos(2<em>x</em>) + 1 = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   cos(2<em>x</em>) = -1/2

sin(5<em>x</em>) = 0   ==>   5<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   5<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   5<em>x</em> = 2<em>nπ</em>   <u>or</u>   5<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = 2<em>nπ</em>/5   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/5

sin(2<em>x</em>) = 0   ==>   2<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   2<em>x</em> = 2<em>nπ</em>   <u>or</u>   2<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = <em>nπ</em>   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/2

cos(2<em>x</em>) = -1/2   ==>   2<em>x</em> = arccos(-1/2) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -arccos(-1/2) + 2<em>nπ</em>

… … … … … …    ==>   2<em>x</em> = 2<em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -2<em>π</em>/3 + 2<em>nπ</em>

… … … … … …    ==>   <em>x</em> = <em>π</em>/3 + <em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + <em>nπ</em>

<em />

(where <em>n</em> is any integer)

5 0
2 years ago
Greg has only nickels and dimes in his money box. He knows that he has more than $10 in the box. Let x represent the number of n
Andrews [41]

Answer: Draw a dashed line to represent the graph of , and shade the portion above the line for positive values of x and y

Step-by-step explanation: Let

x------> the number of nickels in the box

y------->the number of dimes in the box

we know that

so

Multiply by  both sides

-----> inequality that represent the situation

The solution of the inequality is the shaded area above the dashed line for positive values of x and y

The equation of the dashed line is

therefore

the answer is

Draw a dashed line to represent the graph of , and shade the portion above the line for positive values of x and y

4 0
2 years ago
Gabrielle is 12 years younger than Mikhail. The sum of their ages is 76 . What is Mikhail's age?
Over [174]

Answer:

48 years old

Step-by-step explanation:

Let x = Mikhail's age

then x-15 = Gabrielle's age

x + x-15 = 81

2x-15 = 81

2x = 96

x = 48 years old

6 0
2 years ago
Read 2 more answers
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