The amount of ounces of the 7.9% substance is 2 ounces
<h3>How to determine the how many ounces of the 7.9% he used?</h3>
We know that amount m = CV where
- c = concentration and
- V = volume
Let
- m = amount of 3.7 % ,
- m' = amount of 7.9 % and
- M = amount of 6.5 %
We have that m + m' = M
cv + c'v' = CV where
- c = 3.7 % conentration = 0.037
- v = volume of 3.7 % = 1 ounce ,
- c = 7.9% concentration = 0.079,
- v' = volume of 7.9%,
- C = 6.5 % concentration = 0.065 and
- V = volume of 6.5% = v + v'
Since cv + c'v' = CV
Substituting the values of the variables into the equation, we have
3.7% × 1/3.7% + 7.9 %v' = 6.5%(v + v')
3.7% + 7.9 %v' = 6.5%(1 + v')
3.7% + 7.9 %v' = 6.5% + 6.5%v'
7.9%v' - 6.5%v' = 6.5% - 3.7%
1.4%v' = 2.8%
v' = 2.8%/1.4%
v' = 2 ounces
So, the amount of ounces of the 7.9% substance is 2 ounces
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