<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer:
r = 5 cm
Step-by-step explanation:
A = πr²
78.53 = (3.14)r²
divide by 3.14
25 = r²
r = ±5
r = 5
Its a.
Lol taking forever to do stuff is fun.
18 is the answer //////////////////
