8 and 1/5 = 41/5
4 and 2/5 = 2255
41-22=19 so 19/5
19/5=3 with a remainder of 4
so the answer is 3 and 4/5
Answer:
The degrees of freedom are given by:
And the p value is given by:
Since the p value is very low compared to the significance level provided we have enough evidence to conclude that the true deviation is higher than 0.45
Step-by-step explanation:
Information given
represent the confidence level
represent the sample variance obtained
represent the value that we want to test
System of hypothesis
On this case we want to check if the true deviation is higher than 0.45, so then we can create the following system of hypothesis:
Null Hypothesis:
Alternative hypothesis:
The statistic for this case is given by:
Replacing we got
The degrees of freedom are given by:
And the p value is given by:
Since the p value is very low compared to the significance level provided we have enough evidence to conclude that the true deviation is higher than 0.45
Answer:
Mean = 0
Variance = 4/3
Standard Deviation √4/3
a= 0.9
Step-by-step explanation:
If X has a uniform distribution over [a,b] then its Mean is a+b/2 and variance is (b-a)²/12
Here a= -2 and b= 2
Now finding the mean = a+b/2=-2+2/2= 0
Variance = (b-a)²/12=( 2-(-2))²/12= 4²/12= 16/12= 4/3
Standard Deviation = √Variance= √4/3
b) = \int\limits^a_a {\frac{1}{a- (-a)} } \, dx
=1/2a[x]^a_-a= 2a/2a= 1 (applying the limits to the function)
P(−a<X<a) ==1/2 * 2a= a (applying the limits to the function)
P(−a<X<a)= 0.9
a= 0.9
In the given question the limits are -a to a . When we apply these in the above instead of [a,b] we get the above answer.
Answer:
{r,z}
Step-by-step explanation:
U = {r,s,t,u,v,w,x,y,z}
P = {s,t,u,v,w}
Q = {u,v,x,y}
P' means elements in the universe,U, that are not in P.
P'={r,x,y,z}.
Q' means elements in the universe,U, that are not in Q.
Q'={r,s,t,w,z}.
P' intersect Q' means what elements are in common in both lists.
{r,z}
9.45 dollars would be the price