Question

Peter arranges 10 books on a bookshelf. In how many different ways can 10 books be arranged?

Answer 1

Answer;

$\text{3,628,800 ways}$

Explanation;

Here, we want to get the number of ways the 10 books can be arranged

This is a permutation problem

To arrange r out of n items, we can have that done in the following way;

$^nP_r\text{ = }\frac{n!}{(n-r)!}$

So, with this we have the number of ways as;

$^{10}P_{10}\text{ = }\frac{10!}{(10-0)!}\text{ = 3,628,800 ways}$