![\rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}](https://tex.z-dn.net/?f=%5Crule%7B50%7D%7B1%7D%5Clarge%5Ctextsf%7B%5Ctextbf%7B%5Cunderline%7BQuestion%3A-%7D%7D%7D%5Crule%7B50%7D%7B1%7D)
<em>13-r<82</em>
<em />
<em> </em>![\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}](https://tex.z-dn.net/?f=%5Crule%7B50%7D%7B1%7D%5Clarge%5Cblue%5Ctextsf%7B%5Ctextbf%7B%5Cunderline%7BAnswer%20and%20how%20to%20solve%3A-%7D%7D%7D%5Crule%7B50%7D%7B1%7D)
First of all, we need to isolate r (get r by itself). What I Mean by that is
We need to get r by itself on one side of the inequality.
So it should look something like this:-
r<___
So r is all by itself.
How will we get r by itself? Well, First of all, we need to subtract 13 on both sides:-
![\longmapsto\bf{-r < 82-13](https://tex.z-dn.net/?f=%5Clongmapsto%5Cbf%7B-r%20%3C%2082-13)
Simplifying,
![\longmapsto\bf{-r < 69}](https://tex.z-dn.net/?f=%5Clongmapsto%5Cbf%7B-r%20%3C%2069%7D)
Now, is r by itself? Nopes, There's also a minus sign next to it , which indicates that r is multiplied by -1.
So we do the opposite operation and divide both sides by -1:-
(watch what happens)
![\longmapsto\bf{r > -69}](https://tex.z-dn.net/?f=%5Clongmapsto%5Cbf%7Br%20%3E%20-69%7D)
The <u>inequality sign changed from </u>"less than" to "greater than".
This happened because we divided by a negative number on both sides.
<h3>Good luck with your studies.
![\ddot\smile](https://tex.z-dn.net/?f=%5Cddot%5Csmile)
</h3>
#TogetherWeGoFar
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