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Archy [21]
2 years ago
11

13 - r < 82 PLA I NEED THIS

Mathematics
2 answers:
SOVA2 [1]2 years ago
8 0

        \rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

    <em>13-r<82</em>

<em />

<em>       </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

   First of all, we need to isolate r (get r by itself). What I Mean by that is

       We need to get r by itself on one side of the inequality.

      So it should look something like this:-

     r<___

So r is all by itself.

How will we get r by itself? Well, First of all, we need to subtract 13 on both sides:-

\longmapsto\bf{-r < 82-13

Simplifying,

\longmapsto\bf{-r < 69}

Now, is r by itself? Nopes, There's also a minus sign next to it , which indicates that r is multiplied by -1.

So we do the opposite operation and divide both sides by -1:-

(watch what happens)

\longmapsto\bf{r > -69}

The <u>inequality sign changed from </u>"less than" to "greater than".

This happened because we divided by a negative number on both sides.

<h3>Good luck with your studies. \ddot\smile</h3>

#TogetherWeGoFar

\rule{300}{1}

maria [59]2 years ago
5 0

Answer:

r > -69

Step-by-step explanation:

13 - r < 82

subtract 13 from both sides

13 - r - 13 < 82 - 13

- r < 69

to flip the inequality sign, multiply both side by -1 to make r positive:

- r (-1) < 69 (-1)

r > -69

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What are the measures of angles M and N?
romanna [79]

Answer:

mM = 113 and mN = 61

Step-by-step explanation:

In a Cyclic quadrilateral, the rule states that:

The sum opposite interior angles is equal to 180°

In the above diagram, we have cyclic quadrilateral KLMN

According to the rule stated above:

Angle K is Opposite to Angle M

So, Angle K + Angle M = 180°

Angle K = 67°

67° + Angle M = 180°

Angle M = 180° - 67°

Angle M = 113°

Angle L is Opposite to Angle N

so Angle L + Angle N = 180°

Angle L is given as = 119°

119° + Angle N = 180°

Angle N = 180° - 119°

Angle N = 61°

Therefore, Angle M = 113° and Angle N = 61°

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aivan3 [116]
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I need answer on this graphing va substitution.Problem 7 I tried to solve it but not sure that’s correct
Bond [772]

Given the system of equations:

\begin{gathered} 2x+9y=27 \\ x-3y=-24 \end{gathered}

To solve it by substitution, follow the steps below.

Step 1: Solve one linear equation for x in terms of y.

Let's choose the second equation. To solve it for x, add 3y to each side of the equations.

\begin{gathered} x-3y=-24 \\ x-3y+3y=-24+3y \\ x=-24+3y \end{gathered}

Step 2: Substitute the expression found for x in the first equation.

\begin{gathered} 2x+9y=27 \\ 2\cdot(-24+3y)+9y=27 \\ -48+6y+9y=27 \\ -48+15y=27 \end{gathered}

Step 3: Isolate y in the equation found in step 2.

To do it, first, add 48 to both sides.

\begin{gathered} -48+15y=27 \\ -48+15y+48=27+48 \\ 15y=75 \end{gathered}

Then, divide both sides by 15.

\begin{gathered} \frac{15y}{15}=\frac{75}{15} \\ y=5 \end{gathered}

Step 4: Substitute y by 5 in the relation found in step 1 to find x.

\begin{gathered} x=-24+3y \\ x=-24+3\cdot5 \\ x=-24+15 \\ x=-9 \end{gathered}

Answer:

x = -9

y = 5

or (-9, 5)

Also, you can graph the lines by choosing two points from each equation, according to the picture below.

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