In cell H5, enter a formula using the IF function that tests whether the numbe
2 answers:
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Answer:
listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
listString = [ ]
for i in range(14):
if listNumbers[i]%2!=0 and listNumbers[i]%5==0:
listString.append("five odd")
elif listNumbers[i]%5==0 and listNumbers[i]%2==0:
listString.append("five even")
elif listNumbers[i]%2==0:
listString.append("even")
elif listNumbers[i]%2!=0:
listString.append("odd")
print(listNumbers)
print(listString)
Explanation:
In python programming language;
- Create two lists
- The first is a list of numbers and initialize it with random values: listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
- The second list is empty and will hold the string values listString = [ ]
- Use a for loop to iterate over all the elementts in the list of numbers
- Use the modulo operator (%) to chech for multiples of particular numbers as stipulated by the question
- Use combination of if/elif statements for each condition
- Use the .append method to add the elements into the list of strings
- finially output both lists
See attached code and output
Answer:
a. see explaination
b. 0.632
Explanation:
Packet switching is a method of grouping data that is transmitted over a digital network into packets. Packets are made of a header and a payload.
See attachment for the step by step solution of the given problem.
