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Vinvika [58]
3 years ago
11

Yet another variation: A better packet switched network employs the concept of acknowledgment. When the end user’s device receiv

es a packet correctly it sends an acknowledgment to the sender. Here too, a packet is received correctly with probability p, but the sender keeps sending copies of a given packet until a copy is correctly received (signaled by acknowledgment). Let random variable N be the number of times the same message packet is sent. a) Find the PMF PN (n). b) To avoid excessive delays (too many repeated transmissions of same packet), it is required that the network maintain P[N < 4] > 0.95. Find the minimum value of p that will satisfy this requirement

Computers and Technology
1 answer:
dlinn [17]3 years ago
7 0

Answer:

a. see explaination

b. 0.632

Explanation:

Packet switching is a method of grouping data that is transmitted over a digital network into packets. Packets are made of a header and a payload.

See attachment for the step by step solution of the given problem.

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Bytes are typically represented with a lowercase b and bits with an uppercase B.<br> true or false
34kurt

Answer:

False

Explanation:

Byte(B) is uppercase

bit(b) is lowercase

Good way to remember is that its takes 8 bits makes a byte. In other word, a byte is bigger than a bit so it makes sense that byte is uppercase.

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3 years ago
Drag each tile to the correct box.
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Read 2 more answers
Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
ddd [48]

Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
  14.        listNumber.append(min(listNumber))
  15.    
  16.    print(listNumber)
  17. modifyList([-1,-99,-81])
  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

At last we can print the listNumber (Line 17).

If we test our function using the three sets of input list, we shall get the following results:

[-1, -99, -81, -99]

[1, 99, 8, 99]

[-1, 99, -81]

3 0
3 years ago
Your friend wants to know about Microsoft Expression Web 4.
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3 0
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Which is the most effective way to demonstrate being prepared for an interview
postnew [5]

Answer:

Companies want people who know more about them and rather have someone who is interested in the company than someone who is just looking for a way to get payed.

Explanation:

7 0
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