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gavmur [86]
1 year ago
15

Pls answer question will mark brainliset tyty

Chemistry
2 answers:
kirza4 [7]1 year ago
5 0

Answer:

Forests are a renewable resource

marin [14]1 year ago
3 0

Answer: B. Forests

Explanation:

This is because, as part of its biological cycle, carbon is taken up by trees and becomes forest biomass that eventually dies, decays, and releases carbon that is in turn taken back up by renewed forest growth.

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<span>Aqueous solution is something where water is solvent. When the aqueous solution is saturated in both potassium chlorinate and carbon dioxide gas at 85C, the carbon dioxide bubbles out of the solution. The hydrophobic substances do not get dissolved in the water.</span>
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3 years ago
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Use the chart below to answer the question.
lilavasa [31]

Answer:

Species M. furo and F. catus

Explanation:

When you look at their family name, both species have -<em>lidae </em>at the end, indicating that they are more closely related.

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3 years ago
an electric current causes water to be transformed into hydrogen and oxygen gasses a physical change or a chemical change
Natalija [7]
Physical change because ther is force which is the electric current
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3 years ago
Calculate the molarity (M) of a solution containing 49.0 grams of H3PO4 in 500 mL of solution.
vlada-n [284]

Answer

The molarity (M) of the H3PO4 solution = 1.0 M

Explanation

Given:

Mass of H3PO4 = 49.0 grams

Volume of the solution = 500 mL = 500/1000 = 0.5 L

What to find:

The molarity (M) of the H3PO4 solution.

Step-by-step solution:

Step 1: Convert 49.0 grams H3PO4 to moles using the mole formula.

Mole=\frac{Mass}{Molar\text{ }mass}

The molar mass of H3PO4 = 97.994 g/mol

So,

Mole=\frac{49.0\text{ }g}{97.994\text{ }g\text{/}mol}=0.50\text{ }mol

Step 2: Calculate the molarity of the solution using the molarity formula.

Molarity=\frac{Mole}{Volume\text{ }in\text{ }L}

Putting mole = 0.50 mol and volume = 0.50L into the formula, we have;

Molarity=\frac{0.50mol}{0.50L}=1.0\text{ }M

The molarity (M) of the H3PO4 solution = 1.0 M

5 0
1 year ago
Describe one everyday situation in which it would be useful to identify unknown substance. Explain how you would identify the su
leonid [27]

Here are three everyday situations which it would be useful to identify unknown substances:

1. When you have two clear substances with no labels yet you are not sure which substance is water and which one is not and not knowing what this unknown chemical might do.

2. A stain on your clothes

3. When you are not feeling well and your sense of taste is not functioning well.

The ways that these can be identified is first, start by the appearance, for example the state, color, texture, etc. And secondly, use your sense of smell. This sense is also helpful in identifying whether the substance is something strong or not.





5 0
3 years ago
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