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cupoosta [38]
3 years ago
10

An aqueous solution is saturated in both potassium chlorate and carbon dioxide gas at room temperature. what happens when the so

lution is warmed to 85 ∘c

Chemistry
2 answers:
alexandr1967 [171]3 years ago
8 0

Answer:

Carbon dioxide will evolve from solution.

Explanation:

As a general rule gases are less soluble in water as temperature increases. Since a gas saturated solution is being heated gas is expected to evolve.

Gas solubility as function of water temperature is attached.

Svetach [21]3 years ago
3 0
<span>Aqueous solution is something where water is solvent. When the aqueous solution is saturated in both potassium chlorinate and carbon dioxide gas at 85C, the carbon dioxide bubbles out of the solution. The hydrophobic substances do not get dissolved in the water.</span>
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Answer:

Ca(OH)2 molecular weight. Molar mass of Ca(OH)2 = 74.09268 g/mol. This compound is also known as Calcium Hydroxide. Convert grams Ca(OH)2 to moles or moles Ca(OH)2 to grams. Molecular weight calculation: 40.078 + (15.9994 + 1.00794)*2 ››

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The Earth's moon is unusually large. Two popular theories of the moon's origin include the "sister world" hypothesis, which stat
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3 0
3 years ago
What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi
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Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0
3 years ago
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