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2 years ago

My math teacher just gave me a super hard question WILL GIVE CROWN!!!!

Mathematics

2 answers:

saveliy_v [14]2 years ago

6 0

This one is super difficult, I see your struggle but the answer is A.

Luden [163]2 years ago

3 0

Answer:

Step-by-step explanation:

i just did it on my test too and i got it right

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Need help Asap thank you in advance

julia-pushkina [17]

Answer:

$12x^4-20x^2+32x=4x(3x^3-5x+8)$

Step-by-step explanation:

Common Factors

An algebraic expression that is formed by sums or subtractions of terms can be factored provided there are numeric or variable common factors in all the terms.

The following expression

$Z=12x^4-20x^2+32x$

Can be factored in the constants and in the variable x.

1. To find the common factor of the variable, we must locate if the variable is present in all terms. If so, we take the common factor as the variable with an exponent which is the lowest of all the exponents found throughout the different terms. In this case, the lowest exponent is x (exponent 1).

2. To find the common factors of the constants, we take all the coefficients:

12 - 20 - 32

and find the greatest common divisor of them, i.e. the greatest number all the given numbers can be divided by. This number is 4, since 12/4=3, 20/4=5 and 32/4=8

3. The factored expression is

$Z=12x^4-20x^2+32x=4x(3x^3-5x+8)$

$\boxed{12x^4-20x^2+32x=4x(3x^3-5x+8)}$

3 0

3 years ago

Given the following coordinates complete the glide reflection transformation.

Romashka [77]

Answer:

$A" = (7,-2)$

$B" = (10,0)$

$C"= (12,-3)$

Step-by-step explanation:

Given

$A = (4,2)$

$B = (7,0)$

$C =(9,3)$

a: Reflect over x-axis

The rule of this is:

$(x,y) \to (x,-y)$

So, we have:

$A' = (4,-2)$

$B' = (7,0)$

$C' = (9,-3)$

b: Shift 3 units left

The rule of this is:

$(x,y) \to (x+3,y)$

So, we have:

$A" = (4+3,-2)$

$A" = (7,-2)$

$B" = (7+3,0)$

$B" = (10,0)$

$C"= (9+3,-3)$

$C"= (12,-3)$

4 0

3 years ago

Jerrica is selling calendars to raise money for a community group she belongs to. A basic calendar sells for $10 and a deluxe ca

Sidana [21]

The correct answer is option B.

Let the basic calendars be = x

Let the deluxe calendars be = y

Total calendars are = 72 , so equation becomes:

$x+y=72$ .............(1)

Cost of 1 basic calendar = $10

So, cost of all basic calendars will be = 10x

Cost if 1 deluxe calendar = $15

So, cost of all deluxe calendars = 15y

As given, the number of deluxe calendars must be greater than or equal to 3 times the number of basic calendars, the equation becomes

y=3x ...............(2)

Putting the value of y from (2) in (1)

$x+y=72$

$x+3x=72$

$4x=72$

x=18

As, y=3x

y= $3\times18=54$

So we have 18 basic calendars and 54 deluxe calendars.

Cost of 18 basic calendars will be= $18\times10=180$

Cost of 54 deluxe calendars will be = $54\times15=810$

So total amount is = $990

Hence, the maximum revenue is $990.

4 0

3 years ago

Read 2 more answers

What is the value of X? A: x=18 B: x=48 C: x=82 D: x=98

snow_tiger [21]

The two given angles when added together needs to equal 180 degrees ( straight line)

X + 34 + 2x + 2 = 180

Combine like terms:

3x +36 = 180

Subtract 36 from both sides:

3x = 144

Divide both sides by 3:

X = 48

The answer is B.

5 0

3 years ago

Read 2 more answers

Why might researchers want to estimate the number of animals in a population?

Yuliya22 [10]

Answer:

If a researcher select less number of animals it may lead to missing of any significant difference even if it exist in population and if more number of animals selected then it may lead to unnecessary wastage of resources and may lead to ethical issues.

Step-by-step explanation:

6 0

2 years ago