The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
no
Step-by-step explanation:
because I no and nono and y
The solution to the equation is x = -5
<h3>How to determine the value of x?</h3>
The equation is given as:
the quantity 2x minus 20 divided by 3 = 2x
Rewrite properly as
(2x - 20)/3 = 2x
Multiply through by 3
2x - 20 = 6x
Collect like terms
6x - 2x = -20
This gives
4x = -20
Divide by 4
x = -5
Hence, the solution to the equation is x = -5
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The answer is (-18, -2). Just multiply by 2!