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qwelly [4]
1 year ago
8

Two new skyscrapers, North and South, are being built. The height. N, in feet of the xth floor above the ground floor for thr No

rth Tower is shown in the graph of N (x). The height, S, in feet of the xth floorabove the ground floor for the South Tower is shown on graph S (x). Dayton says that the floors of the North Tower are taller than the floors of the South Tower. He also says that the ground floor of the South Tower is taller than the ground floor of the North Tower. Analyze the graphs of N (x) and S (x) to explain whether Dayton's statements are correct.

Mathematics
1 answer:
Bad White [126]1 year ago
3 0

There are 2 steaight lines , representing height an base of two buildings

Floor N > Floor S

Ground S > Ground N

Height = Ground x Floor

Then there must be some point that

Height N = Height S

this point is aprox at 2 floors

then Dayton was right

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6,435,920,178 in expanded form
VMariaS [17]
6,435,920,178\\=6,000,000,000+400,000,000+30,000,000+5,000,000\\+900,000+20,000+100+70+8
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Part a - obtaining conversion factors from unit equality relationships in an experiment you are performing, your lab partner has
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Solution:

As we given that 1 inch=2.54 cm

then using this conversion factor we can write  28.4 inch=28.4* (1 inch)

and further it can be written as

28.4* (1 inch)*(2.54 cm/1 inch)=28.4*2.54 cm= 72.136 cm

Hence the required conversion factor is 2.54 cm/1 inch as we can see from the above calculation.

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3 years ago
Where does the graph of y= sin x from x = 0 to x = 217 start?
choli [55]

Answer:

B) at an x-intercept

Step-by-step explanation:

Hope this helps :))

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3 years ago
Answer Please---Due today!!!
Angelina_Jolie [31]

Answer:

14/44 or 7/22

because 44 is the total and the total number of latin cds are 14

so 14/44 simplified would be 7/22

hope it helped

Step-by-step explanation:

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5 0
2 years ago
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Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
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