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3 years ago

5

I will give brainliest please help me easy math question!!!!!!!!!!!

2 answers:

maria [59]3 years ago

7 0

Answer:

1. -1/2b

2. 3a/b^2

3. 3b^2/1a^2

4. -1a^2b/2

Step-by-step explanation:

Simplified answers and then the variables cancel out each out as much as they can (That's the best way to explain it)

Nookie1986 [14]3 years ago

3 0

Answer: -4a/8ab goes with -1/2b

-9b^3/-3a^2b goes with 3a/b^2

3a^4/1a^3b^2 goes with 3b^2/1a^2

5a^4b/-10a^2 goes with-1a^2b/2

Step-by-step explanation:

When ever you do problems with fractions make sure you combine like terms. If you have multiple a’s, in this case you should divide them. When you divide a’s with exponents you always subtract the exponents by each other. Hope this helps!

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pamela claims that if you multiply a fraction that is negative by another fraction that is negative, the product will also be ne

svetoff [14.1K]

Pamela is incorrect. When you multiply anything negative by a negative, the product will always be a positive. Because the two negative signs cancel each other out.

5 0

3 years ago

A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn

tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

$(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)$

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.

The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

$\sigma = \dfrac{ 11}{\sqrt{121}} = 1$

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

$(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)$

That's probably the answer they're looking for.

4 0

3 years ago

Two sides of a triangle measure 8 cm and 15 cm. Whi[:h could be the length of the third side?

lutik1710 [3]

18 cm is correct .

Step-by-step explanation:

The sum of two smaller sides is greater that the largest side.

It is given that the two sides of a triangle measure 8 cm and 15 cm.

Case 1: Let 8 cm and 15 cm. are smaller side. So,

<em>Third side < 8 + 15</em>

<em>Third side < 23</em>

<em>It means 3rd side must be less than 23</em>

<em>Case 2: Let 15 cm is the largest side.</em>

<em>15 < Third side + 8</em>

15 - 8 < Third side

7 < Third side

It means 3rd side must be greater than 7.

Since only 18 is less than 23 and greater than 7, therefore the possible length of third sides is 18 cm and option 2 is correct.

8 0

3 years ago

What is the slope of the line between (3,-4) and (-2, 1)?<br> O 1<br> 02.<br> O-2<br> O-1

natka813 [3]

Answer:

-1……..........................

4 0

3 years ago

Read 2 more answers

Why is the value of q?

Rudiy27

Given:

QSR is a right triangle.

QT = 10

TR = 4

To find:

The value of q.

Solution:

Hypotenuse of QSR = QT + TR

= 10 + 4

= 14

Geometric mean of similar right triangle formula:

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$$\Rightarrow \frac{14}{q} =\frac{q}{4}$

Do cross multiplication.

$$\Rightarrow14\times 4 =q\times q$

$$\Rightarrow 56 =q^2$

Switch the sides.

$$\Rightarrow q^2 =56$

Taking square root on both sides.

$\Rightarrow q =2 \sqrt{14}$

The value of q is $2 \sqrt{14}$ .

8 0

3 years ago