Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
from what i understand the answer is 5 + 2 5+2 5+2 but idk thats what my sunt said & shes a 8 grade math teacher
Step-by-step explanation:
i asked my aunt
You have to take the x to on side and numbers to the other but in order to do that you'll have to divide -3 from both sides and then just solve the equation.
Subtract 2_5/8 minus 1_1/3:
First, get the fractions to have a common denominator by multiplying the denominators together: 8*3 = 24
Rewrite both fractions with this new denominator:
5/8 needs to be multiplied by 3 on top and bottom to make it have a denominator of 24:
5/8 * 3/3 = 15/24
1/3 needs to be multiplied by 8 on top and bottom to make it have a denominator of 24:
1/3 * 8/8 = 8/24
Now that the fractions have been rewritten with the same denominator, subtract the mixed numbers:
2_15/24 - 1_8/24
Whole numbers:
2 - 1 = 1
Fractions:
15/24 - 8/24 = 7/24.
The can of condensed soup contains 1_7/24 cup
