Plzzzzzz help! What is the area of figure A?

Mathematics

1 answer:

zloy xaker [14]2 years ago

3 0

Answer:

A=24m^2

Step-by-step explanation:

to find the area of this figure you can approach it multiple ways, the simplest way is to split it into two rectangles

respectively one 6m by 3m and another 3m by 2m

find the areas of each rectangle and add them both to get the total area of the figure

(6m*3m)+(3m*2m)=(18+6)m^2=24m^2

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Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

Hope this wasn't too confusing! I'll answer any questions.

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2 years ago

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What is mLA?<br><br> Enter your answer in the box.

olga nikolaevna [1]

Answer:

84 degrees

Step-by-step explanation:

To find the measure of angle a you must first find m<CED. To do this remember every triangle has a measure of 180.

180-(43+35)=102, that means m<CED=102. Also m<CED=m<AEB because they are vertical angles. So now do the same operation but for the other triangle 180-(102+18)=84. So m<A=84.

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Answer:

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Step-by-step explanation:

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