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2 years ago

Hello could you please help me with this problem? Write the standard form of the equation y+4=-12/7(x-1).

Mathematics

1 answer:

kherson [118]2 years ago

3 0

Given:

$y+4=-\frac{12}{7}\mleft(x-1\mright)$

express the equation in standard form,

$\begin{gathered} y+4=-\frac{12}{7}(x-1) \\ 7(y+4)=-12(x-1) \\ 7y+28=-12x+12 \\ 7y+12x=12-28 \\ 12x+7y=-16 \end{gathered}$

Answer:

$12x+7y=-16$

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Confidence interval

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$

And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

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And replacing we got:

$\bar X= 8.98[/tex[tex]s = 1.29$

The confidence interval for the mean is given by the following formula:

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The degrees of freedom are given by:

$df=n-1=12-1=11$

The Confidence level is 0.95 or 95%, the value of significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value would be $t_{\alpha/2}=2.20$

Repplacing the info we got:

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$ And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

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