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Serhud [2]
1 year ago
5

Find an expression which represents the difference when (2x − 6) is subtracted

Mathematics
1 answer:
Sloan [31]1 year ago
4 0

Answer:

-2x + 8

Step-by-step explanation:

(2x - 6) is subtracted from (7 - 5).

First term that into an equation.

Because our first term is being subtracted from our second one, our equation is written as:

(7 - 5) - (2x - 6).

Simplify the first term by subtracting:

7 - 5 = 2

Now simplify the second term by multiplying 2x - 6 by -1 to get them out of the parenthesis. We do this because there is a negative sign in front of it.

-1 (2x - 6)

-2x + 6

Now our equation is:

2 - 2x + 6

Combine like terms:

2 + 6 = 8

So -2x + 8

(2x - 6) subtracted from (7 - 5) is -2x+8

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There are 20 students in Lynn's class. 12 of the students are in choir and 8 are in band. Write a fraction, in simplest form, to
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Andy is considering taking a loan to remodel his kitchen. He is offered a loan by his bank for five years and an annual interest
Aleksandr-060686 [28]

Using compound interest, it is found that the maximum amount of money he can borrow is of $8,700.

------------------------

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal).
  • n is the number of times that interest is compounded per year.
  • t is the time in years.

Maximum <u>monthly payments of $200 per month per five years</u>, thus:

A(t) = 5 \times 200 \times 12 = 12000

  • Interest rate of 6.5%, thus r = 0.065.
  • Monthly payments, thus n = 12.
  • Five years, thus t = 5.
  • The <u>amount he can borrow </u>is the principal.

A(t) = P(1 + \frac{r}{n})^{nt}

12000 = P(1 + \frac{0.065}{12})^{60}

1.38282P = 12000

P = \frac{12000}{1.38282}

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To the nearest 100, $8,700.

The maximum amount of money he can borrow is of $8,700.

A similar problem is given at brainly.com/question/15340331

5 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

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