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expeople1 [14]
2 years ago
11

Solve: 5 | x + 2 | + 2 > 7 The answer has the form: ( − ∞ , A ) ∪ ( B , ∞ ) ( A , B ) State your solution using interval nota

tion like above:

Mathematics
1 answer:
aliina [53]2 years ago
7 0

Given:

5|x-3|+3>7

Aim:

We need to find the value of x.

Explanation:

Subtract 3 from both sides of the equation.

5|x-3|+3-3>7-3

5|x-3|>4

Divide both sides of the equation by 5.

\frac{5}{5}|x-3|>\frac{4}{5}

|x-3|>\frac{4}{5}

Square both sides.

(x-3)^2>(\frac{4}{5})^2

(x-3)^2>\frac{16}{25}

x^2-6x+9>\frac{16}{25}

multiply

x^2-6x+9>\frac{16}{25}

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3 0
3 years ago
Please Help <3 Please Help <3
nadezda [96]

Hey, there! For this question, we can just start by plugging in the known values. (f + g)(x) can be rewritten as (\frac{x}{2} - 3 + 3x^2 + x - 6)(x).

Combine like terms: (\frac{x}{2} + x - 3 - 6 + 3x^2)(x)

If you add x to \frac{x}{2}, x will become \frac{2x}{2}, which means that x/2 + x = 3/2x.

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Read 2 more answers
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