Question

Solve: 5 | x + 2 | + 2 > 7 The answer has the form: ( − ∞ , A ) ∪ ( B , ∞ ) ( A , B ) State your solution using interval notation like above:

Answer 1

Given:

$5|x-3|+3>7$

Aim:

We need to find the value of x.

Explanation:

Subtract 3 from both sides of the equation.

$5|x-3|+3-3>7-3$

$5|x-3|>4$

Divide both sides of the equation by 5.

$\frac{5}{5}|x-3|>\frac{4}{5}$

$|x-3|>\frac{4}{5}$

Square both sides.

$(x-3)^2>(\frac{4}{5})^2$

$(x-3)^2>\frac{16}{25}$

$x^2-6x+9>\frac{16}{25}$

multiply

$x^2-6x+9>\frac{16}{25}$