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2 years ago

I really need it 20 Points for this plz help me I beg u

Mathematics

1 answer:

Lemur [1.5K]2 years ago

3 0

I know that when you are explaining, you need to add in all of the work that you did.

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(1+tan^2 A)cot A/cosec^2 A= tanA

Rufina [12.5K]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

1 + tan²A = sec²A , secA = $\frac{1}{cosA}$ , cosecA = $\frac{1}{sinA}$ , cotA = $\frac{cosA}{sinA}$ , tanA = $\frac{sinA}{cosA}$

Consider the left side

$\frac{(1+tan^2A)cotA}{cosec^2A}$

= $\frac{sec^2AcotA}{cosec^2A}$

= $\frac{\frac{1}{cos^2A}(\frac{cosA}{sinA}) }{cosec^2A}$

= $\frac{\frac{1}{cosAsinA} }{\frac{1}{sin^2A} }$

= $\frac{1}{cosAsinA}$ × sin²A

= $\frac{sinA}{cosA}$

= tanA = right side , thus proven

4 0

2 years ago

Teru burned about 1,000 calories downhill skiing before lunch. If she plans to ski for a total of 5 Hours

Evgesh-ka [11]

Answer:

From all the information i have i guess it would be 5000 or something like that

Step-by-step explanation:

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you

5 0

2 years ago

1,160 divides by 8. PLEAAE HELP

solniwko [45]

Answer:

145

Step-by-step explanation:

0 1 4 5

8 1 1 6 0

- 8

3 6

- 3 2

4 0

- 4 0

8 0

3 years ago

Read 2 more answers

A parabola opens down and its vertex is (2, 5). What is the range of this function?

Margaret [11]

The range of the parabola that opens down and has its vertex as (2, 5) is (b) $(-\infty,5]$

<h3>Vertex</h3>

The vertex of a parabola can represent the minimum or the maximum point in the parabola

The vertex of the parabola is given as:

$(h,k) = (2,5)$

<h3>The range</h3>

The range of a function is the set of output values the function can take

From the question, we understand that the parabola opens down.

This means that, the vertex of the parabola is a maximum.

Hence, the range of the parabola is $(-\infty,5]$