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levacccp [35]
1 year ago
10

30 POINTS!!!

Mathematics
1 answer:
Daniel [21]1 year ago
8 0

The unit rate that corresponds to the proportional relationship shown in the given graph above is: 4/3 cm/s.

<h3>How to Find the Unit Rate of a Proportional Graph?</h3>

The unit rate of a proportional graph is determined using the formula below:

k = y/x, where x and y are coordinates of any point on the line.

Thus, to find the unit rate of a proportional graph, pick the coordinates of any point on the line and find k = y/x.

From the given graph, let's pick the indicated point on the line having the coordinates, (12,16). Find k:

Unit rate (k) = 16/12

Simplify

Unit rate (k) = 4/3

Therefore, the unit rate that corresponds to the proportional relationship shown in the given graph above is: 4/3 cm/s.

Learn more about proportional graph on:

brainly.com/question/23318486

#SPJ1

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Please solve this for me!! its from khan academy
viva [34]

<u>Given</u>:

The given triangle ABC is a right angled triangle.

The length of AC is 4 units.

The measure of ∠B is 20°

We need to determine the length of BC.

<u>Length of BC:</u>

The length of BC can be determined using the trigonometric ratio.

Thus, we have;

tan \ \theta=\frac{opp}{adj}

From the figure, the side opposite to the angle is AC and adjacent is BC.

Substituting opp = AC and adj = BC, we get;

tan \ 20^{\circ}=\frac{AC}{BC}

Substituting AC = 4, we have;

tan \ 20^{\circ}=\frac{4}{BC}

Simplifying, we have;

BC=\frac{4}{tan \ 20^{\circ}}

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Find the equation of the line with the given properties: passes<br> through (2,3) and (2,9).
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8 0
3 years ago
Co-ordinate Geometry
saul85 [17]

Answer:

The value of a  = 14

Step-by-step explanation:

Given

(x₁, y₁) = (2, 4)

(x₂, y₂) = (6, a)

(x₃, y₃) = (-1, 1)

A = 9 sq.units

Area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃) is:

A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}

substituting the values (x₁, y₁) = (2, 4), (x₂, y₂) = (6, a), (x₃, y₃) = (-1, 1), A = 9 in th formula

A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}

9=\frac{\left|2\left(a-1\right)+6\left(1-4\right)+-1\left(4-a\right)\right|}{2}

Multiply both sides by 2

\frac{2\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|}{2}=9\cdot \:2

simplify

\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|=18

As the area is always positive.

so

2\left(a-1\right)+6\left(1-4\right)-1\cdot \left(4-a\right)=18

2\left(a-1\right)-18-\left(4-a\right)=18

Add 18 to both sides

2\left(a-1\right)-18-\left(4-a\right)+18=18+18

simplify

2\left(a-1\right)-\left(4-a\right)=36

3a-6=36

3a=42

Divide both sides by 3

\frac{3a}{3}=\frac{42}{3}

a=14

Thus, the value of a  = 14

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3 years ago
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