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jekas [21]
2 years ago
14

PLEASE ANSWER ASAP1. The length of a bookshelf is 5 ft. The length of a model of this bookshelf is 3 ft. Find the scale of the m

odel to the bookshelf. Enter your answer in the box.2. A rectangular garden has a length of 8 ft and a width of 4 ft. A smaller garden was made, using a scale of 3:4 . Find the dimensions of the smaller garden. Enter your answers in the boxes.
Mathematics
1 answer:
klemol [59]2 years ago
7 0

1.

The scale factor would be:

3\colon5

2.

Divide each original dimension by 4 and then multiply by 3, as following:

\begin{gathered} \frac{8ft}{4}\cdot3=6ft \\  \\ \frac{4ft}{4}\cdot3=3ft \end{gathered}

The smaller garden has a length of 6 ft and a widht of 3 ft

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The ratio of blue skittles to red skittles in Tayler's bag is 3 to 4. If there are 20 red
adoni [48]

Answer:

Tayler has 35 SHKITTLES IN ALL

Step-by-step explanation:

Since Tayler has 20 red Skittles, and the ratio of blue skittles to red skittles is 3 to 4, that means that Tayler has 3/4 as many blue skittles as she does red skittles. 3/4 of 20 is 15

20 + 15 = 35

Thus, Tayler has 35 skittles

SHKITTLES lol

6 0
3 years ago
Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)
Triss [41]

g(r,\theta)=(r\cos\theta,r\sin\theta,\theta)\implies\begin{cases}g_r=(\cos\theta,\sin\theta,0)\\g_\theta=(-r\sin\theta,r\cos\theta,1)\end{cases}

The surface element is

\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

and the integral is

\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

=\displaystyle2\pi\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac\pi4(132\sqrt{17}-\sinh^{-1}4)

###

To compute the last integral, you can integrate by parts:

u=r\implies\mathrm du=\mathrm dr

\mathrm dv=r\sqrt{1+r^2}\,\mathrm dr\implies v=\dfrac13(1+r^2)^{3/2}

\displaystyle\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac r3(1+r^2)^{3/2}\bigg|_0^4-\frac13\int_0^4(1+r^2)^{3/2}\,\mathrm dr

For this integral, consider a substitution of

r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds

\displaystyle\int_0^4(1+r^2)^{3/2}\,\mathrm dr=\int_0^{\sinh^{-1}4}(1+\sinh^2s)^{3/2}\cosh s\,\mathrm ds

\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds

=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds

and the result above follows.

4 0
4 years ago
When making sugar skulls we made 5 small ones for every 7 large ones we made. If we made 132 sugar skulls altogether, how many w
Zina [86]

Okay so first,

Confirm: Every time we have 7 large sugar skulls, that also makes 5 large sugar skulls. So if you have 132 <u>ALTOGETHER</u>, then you'd need to do some multiplication/division. First, divide 132 by 5, that equals 26 small sugar skulls. Lastly, 132 ÷ 7 = 18 large sugar skulls. So there are 26 small sugar skulls and 18 large sugar skulls.

(I hope that was right, I tried my best :)

4 0
3 years ago
Im confused, help please?
professor190 [17]
I think it’s g(0)=0, g(1)=1, and g(-1)=1
6 0
3 years ago
Read 2 more answers
I need a math wizard!! Anyone know the answer?
Dafna11 [192]

Answer:

SinA = CosB

SinB = CosA

CosA = SinB

CosB = SinA

7 0
3 years ago
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