Answer:
x = 14.48
Step-by-step explanation:
first we have to see that we have the measurements from all sides
and we know that the angle between side 21 and 20 is 90 degrees
well to start we have to know the relationships between angles, legs and the hypotenuse.
a: adjacent
o: opposite
h: hypotenuse
sin α = o/h
cos α= a/h
tan α = o/a
let's take the left angle as α
sin α = 21/29
α = sin^-1 (21/29)
α = sin^-1 (0.7241)
α = 46.397
Now we do the same with the smaller triangle
tan α = o/a
sin 46.397 = x/20
0.724 = x/20
0.724 * 20 = x
14.48 = x
x = 14.48
if we want to check it we can do the same procedure with the other angle
1. First, we need to approximate <em>the radius</em>. That is the distance from that middle point to the edge. The broom is about half the distance. That means that the radius is about <em>10 feet</em>. Also, multiplying the radius by π will get you nowhere. To find the area, you need to use the equation <em>A = πr²</em>. We know know that r = 10, so 10²π ≈ 100 * 3.1 = 310 ft².
2. Complementary angles <em>add up to 90°, which forms a right angle</em>. Supplementary angles <em>add up to 180°, which forms a straight angle, or a line</em>. We can ignore A and B, since there isn't any right angles. Also, ∠RVS makes a straight line with ∠SVT and ∠RVU. From our options, we can see that C has the fitting description.
Answer:
If the x is a multiplying sign then the answer is 6, but
if the x is the letter x then it will be x=4
Answer:
Given statement is TRUE.
Step-by-step explanation:
Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.
We know that corresponding angles formed by transversal line are congruent.
Hence ∠JKL = ∠ MLK ...(i)
Now consider triangles JKL and MLK
JK = LM {Given}
∠JKL = ∠ MLK { Using (i) }
KL = KL {common sides}
Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.
Hence given statement is TRUE.
The Lesser Sooty Owl is a strictly nocturnal bird. Hides & sleeps during the day in dense foliage, between tangles of aerial roots, in all kinds of crevices, or beneath overhanging banks. Hunts in clearings and near roads, but also inside forest.
