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muminat
2 years ago
10

1. Which addition fact can

Mathematics
1 answer:
Andrews [41]2 years ago
5 0

Answer:

The Answer is B 8+ 6=14

Step-by-step explanation:

14-8=6

8+6=14

14-6=8

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What is the derivative of y=ln(ln(x))?
Marysya12 [62]
Y=ln(ln(x)) y'=(1/x)/Ln(x)=1/xln(x)
7 0
3 years ago
Find the distance between the points (-6,-2), (2,7)
Readme [11.4K]

Answer:

d=12.0416

Step-by-step explanation:

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Simply plug in your 2 coordinates into the distance formula to find distance <em>d</em>:

d=\sqrt{(2-(-6))^2+(7-(-2))^2}

d=\sqrt{(2+6)^2+(7+2)^2}

d=\sqrt{(8)^2+(9)^2}

d=\sqrt{64+81}

d=\sqrt{145}

d=12.0416

4 0
3 years ago
Read 2 more answers
Daniel saves 30% of every paycheck. his paycheck last week was 560.
Brut [27]

Answer: if your asking how much he saved then the answer is $168

Step-by-step explanation:

5 0
3 years ago
six times jasons collection of books and one-third of nathans collection add up to 134 books one-third of jasons collection and
atroni [7]
6j + 1/3n = 134...multiply by 3....18j + n = 402
1/3j + n = 31....multiply by 3....j + 3n = 93

the multiplying by 3 is optional...I just did it because it is easier to work with equations when there are no fractions.

18j + n = 402....multiply by -3
j + 3n = 93
----------------
-54j - 3n = - 1206 (result of multiplying by -3)
j + 3n = 93
----------------add
-53j = - 1113
j = -1113/-53
j = 21

j + 3n = 93
21 + 3n = 93
3n = 93 - 21
3n = 72
n = 72/3
n = 24

so Jasons collection (j) consists of 21 books and Nathans collection (n) consists of 24 books

6 0
4 years ago
(−5)3x7(yz)4 / (3)2x2y8z2
g100num [7]

Answer:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

Step-by-step explanation:

Given:

The expression to simplify is given as:

\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}

In order to simplify this, we have to use the law of indices.

1. (ab)^m=a^mb^m

So, (yz)^4=y^4z^4

Substitute this value in the above expression. This gives,

=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)

Now, we use another law of indices.

2. \frac{a^m}{a^n}=a^{m-n}

So,  \frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2

Substitute these values in the above expression. This gives,

=\frac{-15}{6}\times x^5\times y^{-4}\times z^2\\\\=\frac{-5x^5y^{-4}z^2}{2}

Finally, we further simplify it using the law a^{-m}=\frac{1}{a^m}

So, y^{-4}=\frac{1}{y^4}

Therefore, the given expression is simplified as:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

5 0
3 years ago
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