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Schach [20]
2 years ago
12

What steps need to be taken so that quadrilateral ABCD can be transformed to overlap quadrilateral A’B’C’D’ so that their vertic

es match?

Mathematics
2 answers:
Triss [41]2 years ago
5 0

Answer: it’s C- Reflect ABCD about the y axis then rotate it 90 degrees counter clockwise about the origin

Step-by-step explanation:

because when you reflect it it’s like a mirror so C and A would basically switch when you reflect it over the y axis and then your going to rotate it counter clockwise ( turn your paper once to the left) and that’s what C is it matches the graph when you work it out

stiv31 [10]2 years ago
4 0

Answer:

What’s the answer

Step-by-step explanation:

Pls

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The answer is 9 becouse 8+4+3 equals 27 and 27 divided by 3 is 9

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Taylor was asked to solve the system of linear equations
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Id take a guess and say line 1 because the rest looks correct
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3 years ago
A circle with circumference 6 has an arc with a 60° central angle.
Xelga [282]

Answer:

  1

Step-by-step explanation:

60° is 1/6 of the total number of degrees that make up a circle. Then 1/6 of the total circumference that makes up the circle is ...

  (1/6)(6 units) = 1 unit

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5 0
3 years ago
I need help with this plz
Ksju [112]

Answer:

The correct answer is D. 10.

Step-by-step explanation:

If Brandy earns 2 stars for every goal, and she scored 8 goals, then we need to multiply 8 by 2.

8 x 2 = 16

She looses 1/2 a star for every miss, and she missed the goal 12 times. Therefore, we need to multiply 1/2 by 12.

12 x 1/2 = 6

Therefore, Brandy lost 6 stars.

Now, we need to subtract the amount of stars Brandy earned by the amount that she lost.

16 - 6 = 10

Therefore, the correct answer is D. 10.

Hope this helps! :D

5 0
3 years ago
1. Contaminated water is subjected to a cleaning process. The concentration of the
Leokris [45]

Answer:

The concentration of pollutants in the water can be defined as the quotient between the mass of pollutants and the total mass of water.

Assuming that 1L of water weighs 1000 grams, we know that:

Mass of pollutants = 5mg = 0.005g.

Initial concentration = 0.005g/1000g = 0.000005

If we multiply this by 100%, we get the percentage:

0.000005*100% = 0.0005%

Now, the mass of pollutants decreases by 10% each hour.

So if initially, we have 5mg

After one hour, we will have: 5mg - 0.1*5mg = 5mg*(0.9).

After another hour, we will have: 5mg*(0.9) - 0.1*5mg*0.9 = 5mg*(0.9)^2.

And so on, then after n hours, the mass of pollutants will be:

M(n) = 5mg*(0.9)^n

Or we can write this in grams as:

M(n) = 0.005g*(0.9)^n

Then the concentration as a function of time in hours will be:

C(n) = M(n)/1000g = (0.005g/1000g)*(0.9)^n

Notice that the thing between the parentheses is the initial concentration, then if we write this in percentage form:

c(n) = 100%*(0.005g/1000g)*(0.9)^n = 0.0005%*(0.9)

The function that represents the concentration of polution in the water as a function of hours is:

c(n) = 0.0005%*(0.9)

6 0
3 years ago
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