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2 years ago

12

What steps need to be taken so that quadrilateral ABCD can be transformed to overlap quadrilateral A’B’C’D’ so that their vertic

es match?

2 answers:

Triss [41]2 years ago

5 0

Answer: it’s C- Reflect ABCD about the y axis then rotate it 90 degrees counter clockwise about the origin

Step-by-step explanation:

because when you reflect it it’s like a mirror so C and A would basically switch when you reflect it over the y axis and then your going to rotate it counter clockwise ( turn your paper once to the left) and that’s what C is it matches the graph when you work it out

stiv31 [10]2 years ago

4 0

Answer:

What’s the answer

Step-by-step explanation:

Pls

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Solve each absolute value inequality. Graph the solutions on a number line. |x-7|>1

N76 [4]

Answer:

x>8 and x<6

Step-by-step explanation:

well first the values of x-7 have to be greater than 1 or, less than -1

because if x-7=-2 then |-2|=2>1 satisfying the equation

so we have

$x-7>1\\\\x-7+7>1+7\\\\x>8$

and we have

$x-7$

to graph it it goes from (-∞,6)∪(8,∞)

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3 years ago

A city received 18 inches of rain during the first 3 months of the year. If it continues to rain at this rate, how many inches o

Elza [17]

Answer:

72

Step-by-step explanation:

im pretty sure you just have to do 18*4

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2 years ago

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poizon [28]

Algerbratic Expression

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2 years ago

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What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{2};$
$5\cdot 4=20=\overline{7};$
$5\cdot 5=25=\overline{12};$
$5\cdot 6=30=\overline{4};$
$5\cdot 7=35=\overline{9};$
$5\cdot 8=40=\overline{1};$
$5\cdot 9=45=\overline{6};$
$5\cdot 10=50=\overline{11};$
$5\cdot 11=55=\overline{3};$
$5\cdot 12=60=\overline{8}.$

The multiplicative inverse of 5 in $Z_{13}$ is 8.

8 0

3 years ago

Misty correctly determined the equation of the linear function represented by the table of values below to be y = negative 2 x +

iren [92.7K]

Answer:

y = negative 2 x + 9

Step-by-step explanation:

3 0

3 years ago