-45.6 is the answer if you evaluate
Answer:
Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.
Therefore the equation h(t) = 80t – 16t2 becomes 0= 80t – 16t2
Solving the equation for t gives 80t =16t2 or 16t=80 or t=5sec
The object hits the ground 5 seconds after it is launched.
Answer:
A-8
Step-by-step explanation:
Any other higher number plugged in makes the equation false
0 or dot, depending on what course you are taking
Answer:
B.25.12
Step-by-step explanation:
Solution
C=2πr=2·π·4≈25.13274cm
Hope this helps!