Answer:
To prove:
X+Y.Z=(X+Y).(X+Z)
Taking R.H.S
= (X+Y).(X+Z)
By distributive law
= X.X+X.Z+X.Y+Y.Z --- (1)
From Boolean algebra
X.X = X
X.Y+X.Z = X.(Y+Z)
Using these in (1)
=X+X(Y+Z)+Y.Z
=X(1+(Y+Z)+Y.Z --- (2)
As we know (1+X) = 1
Then (2) becomes
=X.1+Y.Z
=X+Y.Z
Which is equal to R.H.S
Hence proved,
X+Y.Z=(X+Y).(X+Z)
Pretty Sure Its B I had this question Too
Answer:
As they triangles are congruent, we can say that, angle A = angle O
So, angle A = 105+25 =130
A = 180 - 130 = 50° all angles in a triangle add up to 180)
Soo 50° is the answer,
I'm not too sure about it but I think this is correct, hope this helps, correct me if I'm wrong....
BAF and FAD I took the test !
Hello from MrBillDoesMath!
Answer:
Perimeter = 60
Height = 18/5
Discussion:
The diagonals of a rhombus bisect each other at right angles. So a rhombus can be viewed as the union of 4 congruent right triangles, each with legs (1/2)*18 = 9 and (1/2) *24 = 12. See attachment. This gives a hypotenuse length of 15 so the Perimeter = 4 *c = 60.
The height ( = altitude) of a rhombus is
= area / length of base
= (1/2) ( (18) * 24) /c
= (1/2) ( 18 * 24) / 60
= 18/5
Thank you,
MrB