Question

A figure is made up of a triangle and a rectangle. The trianglehas a height of 6.5 inches and a base of 11 inches. Therectangle has dimensions of 9 inches x 11 inches. What isthe total area of the figure?

Answer 1

Answer:

d. 134.75 square inches

Explanation:

Given:

For Triangle:

Height = 6.5 inches

Base = 11 inches

For Rectangle:

Dimensions = 9 inches x 11 inches

First, calculate the area of triangle. We use the formula:

$\begin{gathered} A=\frac{bh}{2} \\ \text{where:} \\ b=\text{base} \\ h=\text{height} \end{gathered}$

We plug in what we know.

$\begin{gathered} A=\frac{bh}{2} \\ =\frac{(11)(6.5)}{2} \\ \text{Calculate} \\ A=35.75in^2 \end{gathered}$

Next, we calculate the area of the rectangle. We use the formula:

A= lw

where:

l=length

w=width

So,

A=lw

=(9)(11)

Calculate

A = 99 in^2

The last step is to add the two areas together.

Total Area = Area of Triange + Area of Rectangle

= 35.75 in^2 + 99 in^2

= 134.75 in^2

Therefore, the total area is 134.75 square inches.