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Andrew [12]
1 year ago
9

I really am confused on how to write a proof.

Mathematics
1 answer:
kvasek [131]1 year ago
8 0

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

\begin{gathered} AB=CD \\ BC=AD \end{gathered}

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

\begin{gathered} AE=CE \\ BE=DE \end{gathered}

Hence Proved.

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Complete the missing value in the solution to the equation.<br> y=-2x+4<br> y=-2
anygoal [31]

Answer:

X=3,y=-2

Step-by-step explanation:

This is a simultaneous equation question and we will have to solve using substitution method

So let's solve

y=-2x+4...(1)

y=-2....(2)

Let's substitute (2) into (1)

-2=-2x+4

Substrate 4 from both sides

-6=-2x

Divide both sides by-2

x=3

Substitute the value of x in (1)

y=-2(3)+4

y=-6+4

y=-2

Therefore x is 3,y is -2

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Marge cut 16 pieces of tape each at 3/8 inches long. How much tape did Marge<br> Cut!
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Step-by-step explanation:

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Read 2 more answers
How are the coordinates of the extreme value and the equation from part B in the form y=(x-h)^2-c related.
True [87]

The extreme value of y = (x - h)² - c is the vertex of the equation.

<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

<h3>The equation of a parabola in vertex form</h3>

The equation of a parabola in vertex form with vertex (h', k) is given by

y = a(x - h')² + k and its extreme values are

  • if a > 0  (h', k) is a minimum point and
  • if a < 0 (h', k) is a maximum point.

Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

  • h = h'
  • -c = k and
  • a = 1.

So, the cooordinates of the vertex of y = (x - h)² - c is (h, -c).

Now, since a = 1 > 0, (h, -c) is a minimum point.

So, the extreme value of y = (x - h)² - c is the vertex of the equation.

Learn more about extreme value of a function here:

brainly.com/question/13464558

#SPJ1

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