Answer:
The average value of 
over the interval ![[-2,5]](https://tex.z-dn.net/?f=%5B-2%2C5%5D)
is 
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval ![[-2, 5]](https://tex.z-dn.net/?f=%5B-2%2C%205%5D)
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
The average value of over the interval is .
Answer:
Please stop with this unless its for math. Others need more help :)
Step-by-step explanation:
Unless this was a real math problem please tell me <u>otherwise. </u>
Answer:
The 5 unknown are 1 quarter, 3 dimes, and 1 penny.
A = bh
b = 16
h = 3
A = 16*3
A = 48 square centimenters
I factor it because you can't simplify
2x-8=2(x-4)
X^2+5x+4=(x+1)(x+4)
X^2-16=(x-4)(x+4)
X^2+8x+16=(x+4)(x+4)
