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Margaret [11]
3 years ago
6

Find the area and the circumference of a circle with diameter 6 yd Use the value 3.14 for n , and do not round your answers.

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

Circumference:

Half of 6 is 3 so

2 x 3 x 3.14 = 18.84

Area of A circle:

Radius is 3, so 3^2 = 9

9 x 3.14 = 28.26

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If i have a 83.5 as my grade and let's just say i would get a 70/100 what would be my grade?
daser333 [38]

Answer:

76.75

Step-by-step explanation:

83.5 + 70=  153.5

153.5 / 2 = 76.75

Your grade would be 76.75.

HOPE THIS HELPED

6 0
3 years ago
Please give the best explanation that you can <br><br><br><br><br> Thank you!
k0ka [10]

Answer:

12

Step-by-step explanation:

you see that yb=2 and that zc is double yb so zc=4. adn if ay=6 that means double ay= 12 or 8+4=12

8 0
3 years ago
Can somebody please walked through this, I'm so confused and I have a test in 6 hours...
erastova [34]

Answer:

Q3: x = 4, y = 4, z = 4

Q4: x = 6, y = 0, z = -4

Step-by-step explanation:

Question 3: Simultaneous equations requires us to solve for x, y and z.

Since all three equations have a z in them, I will first solve for z.

Substitute in the first and third equation into the second equation.

First equation: x = 5z - 16

Second Equation: -4x + 4y - 5z = -20

Third equation: y = -z + 8

Substituting in x = 5z - 16 and y = -z + 8 for the x and y in the second equation.

-4(5z - 16) + 4(-z + 8) - 5z = -20

Expand

-20z + 64   - 4z + 32   - 5z = -20

Simplify and solve for z by putting all the numbers on one side and all the z's on the other side of the equals

-20z - 4z - 5z = -20 - 32 - 64

-29z = -116

z = -116/-29

z = 4

Substitute in this z value into the first and last equation and then solve for x and y

x = 5z - 16

x = 5(4) - 16

x = 20 - 16

x = 4

And

y = -z + 8

y = -(4) + 8

y = 4 (Its just a coincidence that they all equal to 4, I promise)

Question 5: A little bit harder of a question. Since the first and second equation both only have y and z, we can solve it using the elimination method.

Rearrange them so that the letters are on one side and numbers on the other side.

First equation: y + 6z = -24

Second equation: z + 2y = -4

I will choose to eliminate the y (You can choose either or)

Multiply the first equation by 2

2(y + 6z = -24)

2y + 12z = -48

Now that 2y is in both equations, we can minus one equation from the other to eliminate the y (I will minus the second from the first)

First Eq: 2y + 12z = -48

Second Eq: z + 2y = -4

2y - 2y = 0y

12z - z = 11z

-48 - (-4) = -44

Type these answers into a new equation

0y + 11z = - 44

Since y is 0, ignore it. Solve for z

11z = -44

z = -44/11

z = - 4

Substitute our z into either the first or second equation and solve for y (It doesnt matter which one you choose, I just did the second equation)

z + 2y = -4

(-4) + 2y = -4

2y = -4 + 4

2y = 0

y = 0

Substitute in our y and z values into the third equation and solve for x

-6x - 6y - 6z = -12

-6x - 6(0) - 6(-4) = -12

-6x - 0 + 24 = -12

-6x = -12 - 24

-6x = -36

x = -36/-6

x = 6

6 0
3 years ago
Read 2 more answers
What is the answer to this problem -8=2u-4
Monica [59]
-8 + 4 = 2u
-4/2 = 2u/2
-2 = u
3 0
3 years ago
Read 2 more answers
Select the correct answer.
Reika [66]

Answer:

A and C

Step-by-step explanation:

8 0
3 years ago
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