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Damm [24]
1 year ago
8

Anyone know how to prove these are equal to one another? I also need all the steps.

Mathematics
1 answer:
IrinaVladis [17]1 year ago
6 0

Answer:

Step-by-step explanation:

it can be simplified to \frac{sec \theta}{cot\theta+tan\theta} =sin\theta  . if you multiply each side by the denominator, it becomes sec\theta=\frac{sin^2\theta}{cos\theta} + cos\theta since tan\theta=\frac{sin\theta}{cos\theta} and cotan is the reciprocal of that. Because sec\theta=\frac{1}{cos\theta} so multiplying each side gives 1=sin^2\theta+cos^2\theta, and sin^2\theta+cos^2\theta is equal to 1.

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When the sun has risen 32 degrees above the horizon, Sandy casts a shadow that is 9 feet 2 inches long. How tall is Sandy, to th
Makovka662 [10]

Answer:

The height of Sandy is 68.74 inches.

Step-by-step explanation:

It is given that the sun has risen 32 degrees above the horizon. It means the angle of elevation is 32°.

Let the height of Sandy be x.

Sandy casts a shadow that is 9 feet 2 inches long.

We know that 1 feet = 12 inches

Using this conversion, we get

Shadow = 9 feet 2 inches = 9(12)+2 = 110 inches

In a right angled triangle,

\tan\theta =\frac{perpendicular}{base}

In triangle ABC,

\tan(\angle C)=\frac{AB}{BC}

\tan(32^{\circ})=\frac{x}{110}

Multiply both sides by 110.

110\tan(32^{\circ})=x

68.73562871=x

x\approx 68.74

Therefore the height of Sandy is 68.74 inches.

8 0
3 years ago
PLEASE HELP!!!!
Lunna [17]

NOTES:

Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:

  • if "a" is positive, then opens UP
  • if "a" is negative, then opens DOWN

Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:

  • the Axis Of Symmetry (x-value) is: x = \frac{-b}{2a}  
  • y-value is found by plugging in the AOS for "x" in the equation

****************************************************************************************

1) y = x² + 11x + 24

  • a = +1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-11}{2(1)}  = -\frac{11}{2}
  • y = (-\frac{11}{2})^{2} + 11(-\frac{11}{2} ) + 24 = -\frac{25}{4}
  • vertex (-\frac{11}{2}, -\frac{25}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)

******************************************************************************************

2) y = -x² - 6x - 8

  • a = -1 so the parabola opens DOWN
  • x = \frac{-b}{2a} = \frac{-(-6)}{2(-1)}  = \frac{6}{-2} = -3
  • y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1
  • vertex (-3, 1) is in Quadrant 2 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)

******************************************************************************************

3) y = x² - 2x + 3

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-(-2)}{2(1)}  = \frac{2}{2} = 1
  • y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2
  • vertex (1, 2) is in Quadrant 1 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). <em>There are no x-intercepts</em>

******************************************************************************************

4) y = x² + 4x + 4

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-4}{2(1)}  = -2
  • y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0
  • vertex (-2, 0) is in Quadrant 2 and is on the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). <em>The x-intercept is the vertex.</em>

Compared to the other four graphs, this is most likely the equation for the rain gauge!

******************************************************************************************

5) y = 3x² + 21x + 30

  • a = +3 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-21}{2(3)}  = -\frac{7}{2}
  • y = 3(-\frac{7}{2})^{2} + 21(-\frac{7}{2} ) + 30 = -\frac{27}{4}
  • vertex (-\frac{7}{2}, -\frac{27}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)

*******************************************************************************************

4 0
3 years ago
Read 2 more answers
How do you Find the acute Angle A when sinA=0.616?
kirill [66]

Answer:

arcsin0.616

Step-by-step explanation:

arcsino.616

4 0
3 years ago
I need help please thank you hurry
Elena-2011 [213]

Answer:

Step-by-step explanation:

To get the other angles you need to do this

110+80+x+x=360

190+2x=360

2x=360-190

2x=170

X=170÷2

X=85

5 0
3 years ago
Almonds cost $15.50 for 6 pounds. Find the unit rate. Round to the nearest cent if necessary.
Salsk061 [2.6K]
15.50 for 6 lbs......15.50/6 =  $ 2.58 per lb
4 0
3 years ago
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