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Otrada [13]
3 years ago
14

What is an equation of a line, in point-slope form, that passes through (1, −7) and has a slope of −2/3

Mathematics
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

D+B 12

Step-by-step explanation:

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A minimum temperature of -4.44°C was recorded at a lake. A minimum temprature of 23.3°C was recorded later on the same day. Dete
GuDViN [60]

Answer:

27.74 is the difference

Step-by-step explanation:

23.3° C - (-4.44° C)

23.3 + 4.44

27.74

5 0
2 years ago
Please send me answer. tomorrow is my exam.​
masha68 [24]

Answer:

The table is attached below and ogive also.

Step-by-step explanation:

Given

The following distribution is given below

First we find the cumulative frequency.

And then we convert it into a less than type ogive.

find the cumulative frequency shown below clearly

And convert it into less than type of cumulative frequency distribution is also done in next table, the daily income is less than daily income upper limit.

In this graph x-axis is daily income and y-axis is number of workers

6 0
3 years ago
A random sample of 17 hotels in Boston had an average nightly room rate of $165.40 with a sample standard deviation of $21.70. T
tensa zangetsu [6.8K]

Answer:

153.158 ; 177.642

Step-by-step explanation:

Given the following:

Sample mean (m) = 165.40

Sample standard deviation (s) = 21.70

Sample size (n) = 17

α = 98%

Confidence interval = m ± z(SE)

z at 98% = 2.326

SE = s/√n

SE = 21.70/√17 = 5.2630230

Hence,

Confidence interval = 165.40 ± 2.326(5.2630230)

165.40 - 12.241791498 OR 165.40 + 12.241791498

153.158 ; 177.642

3 0
3 years ago
Solve 19.9 = 9 y - 8.<br><br> y =
pogonyaev

Answer:

1.3223 is the answer for y

5 0
3 years ago
Read 2 more answers
Find the equation for the plane that contains the line x=−1+3t , y=1+2t, z=2+4t and is perpendicular to the plane containing the
Ivan

Let L be the line given by the vector equation

(-1,1,2) + \lambda(3,2,4) \ , \lambda \in \mathbb{R}.

First, we use the director vectors of the lines L1 and L2 to get the

vector equation of the plane containing them, which we denote by \Pi_1. This is,

\\\\\Pi_1  : (1,-1,5) + \alpha (2,-1,6) + \beta (1,1,-3) \ , \alpha, \beta \in \mathbb{R}\\\\\\

We observe that \vec{N} = (2,-1,6)\times(1,1,-3) = (-3,12,3) \ne (0,0,0). Therefore, the vector equation of \Pi_1 defines a plane and \vec{N} is a normal vector to \Pi_1.

 

Finally, the vector equation for the wanted plane, which we denote by \Pi, is

\Pi : (-1,1,2) + r(3,2,4) + s(-3,12,3), r,s \in \mathbb{R} \ .

Thus, if s = 0, then L \subset \Pi and since \vec{N} is parallel to \Pi, then it is perpendicular to \Pi_1.

8 0
3 years ago
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