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3 years ago

Need Help please fast

Mathematics

1 answer:

pochemuha3 years ago

3 0

I think B not sure tho

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3 years ago

Write a polynomial function that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of 2√ 13 and -2√13

MAVERICK [17]

Answer:

The polynomial function is $x^{2} - 52$

Step-by-step explanation:

A polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ .

In this problem:

The roots are $x_{1} = 2\sqrt{13}$ and $x_{2} = -2\sqrt{13}$

Then

$(x - 2\sqrt{13}) \times (x - (-2\sqrt{13})) = (x - 2\sqrt{13}) \times (x + 2\sqrt{13}) = x^{2} - 2x\sqrt{13} + 2x\sqrt{13} -(2\sqrt{13})^{2} = x^{2} - 52$

The polynomial function is $x^{2} - 52$

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2 years ago

Square root of 342354456

-Dominant- [34]

Answer:

18502.8229198

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2 years ago

Read 2 more answers

Can u pls help me with this thanks

aleksandrvk [35]

Hey!!!

<a and <b are complementary angles.

Those angles which are exactly 90 degree are called complementary angles.

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3 years ago

Can you explain this for me 7-9÷3+6×6×2-4÷2

baherus [9]

Answer:

The Answer Is 74. Your Welcome

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