Answer:
The probability of using one or the other is 36%
Step-by-step explanation:
For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:
Probability of passing Professor Jones math class = 64% =0,64
P(J) = 0.64
Probabiliry of passing Professor Smith's physics class = 32% =0.32
P(S) = 0.32
Probability of passing both is = 30% = 0.30
P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram
We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:
P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%
If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.
Answer:
585 1/2 ?
Step-by-step explanation:
i dont know if you put the whole question but i simplified 4/8 and got 1/2.
so i guess the answer your looking for is 585 1/2 ...
It is going to be 2.95 because 79.65 divided by 27 equals 2.95
have a good day mate!
Answer:
I am attaching a image to understand my proof.
Step-by-step explanation:
PROVE:-
AB = DC
AD = BC
∠ ABD = ∠ BDC (alternate angles are equal )
∠ DBC = ∠ ADB (alternate angles are equal )
∴ Δ ADB ≅ Δ CBD ( by ASA rule )
DC = BA ( corresponding sides of ≅ Δ )
AD = CB ( corresponding sides of ≅ Δ )
Hence it is proved that opposite sides of parallelogram are congruent )
Answer:
See below
Step-by-step explanation:
You cannot find two whole number integers that give a sum of -12 and a product of 6.
-1 + -11 = -12, but (-1)(-11) = 11, which isn't 6
-2 + -10 = -12, but (-2)(-10) = 20, which isn't 6
...and so on...