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Vinil7 [7]
3 years ago
6

1/3 the weight of a bar of gold plus 30 pounds equals the weight of that bar of gold. How much does the bar of gold weigh?​

Mathematics
2 answers:
svp [43]3 years ago
8 0

Answer:

Step-by-step explanation:

Naddik [55]3 years ago
3 0

Answer:1/3

Step-by-step explanation:use https://www.cymath.com/

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What is the volume of the sphere below?
lbvjy [14]

Answer:

Option C

Step-by-step explanation:

sorry if I'm wrong..

4 0
3 years ago
Polygon ABCD will be dilated by a factor of 2 to produce polygon A′B′C′D′. The origin is the center of dilation. Which point wil
deff fn [24]
Since the origin is the center of dilation. Take every vertex in the polygon ABCD and multiply it by 2 since the dilation factor is 2. It will result to polygon A'B'C'D'. Compare then the points given to the new points after dilation.
6 0
3 years ago
On the surface of the moon, the value of g is 1.67 m/s2. What is the horizontal distance traveled during a 2.00-meter high jump
rodikova [14]
To solve this question, you need to find how long jump is. For 2m high with <span>1.67 m/s2 it would be:

h= 1/2 gt^2
2= 1/2 * (1.67) t^2
t^2= 1.67
t= 1.29

If the speed is 20 mph and the jump is 2 second, the distance traveled would be:
20 miles/ hour * 1.29 second * (1 hour/3600second)= 0.007179 miles

If you need to convert it to meter then: </span>0.007179 mile * 1609.34meter/ mile= 11.55 meter
8 0
3 years ago
Serena has attached a 10 inch ribbon to the corners of a frame to hang it on the wall. The frame 9 inches wide. How far above th
kherson [118]

Answer: The hook would be 2.2 inches (approximately) above the top of the frame

Step-by-step explanation: Please refer to the picture attached for further details.

The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (longest side) and AB and BC are the other two sides

5^2 = 4.5^2 + BC^2

25 = 20.25 + BC^2

Subtract 20.25 from both sides of the equation

4.75 = BC^2

Add the square root sign to both sides of the equation

2.1794 = BC

Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches

4 0
3 years ago
A salesperson obtained a systematic sample of size 25 from a list of 500 clients. To do​ so, he randomly selected a number from
dangina [55]

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

First term = 13

Increase each time = 20

Number of clients = 25

So, it forms an arithmetic progression:

So, 25 th term would be

a_{25}=a+(n-1)d\\\\a_{25}=13+(25-1)\times 20\\\\a_{25}=13+24\times 20\\\\a_{25}=13+480\\\\a_{25}=493

Hence, list would look like 13,33,............493.

Therefore, Option 'D' is correct.

3 0
3 years ago
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