Question

problem: report error anabel's horse runs $24$ miles per hour. jackie's horse runs $28$ miles per hour. both horses stand at the starting line of a straight $2$-mile track, and jackie's horse starts running $30$ seconds after anabel's. how many miles from the starting line does jackie's horse catch up to anabel's?

Answer 1

The miles from the starting line does which jackie's horse catch up to Anabel's is 1.4 miles.

What is defined as the rate?

• The unit rate is distinct from the rate, which compares a certain number of units of first quantity to one unit of a second quantity.
• To put it another way, the second quantity with in comparison has always been 1.
• One minute, for example, has 60 seconds. As a result, we can convey that as 60 seconds per minute as a unit rate.

Let the distance covered by Jackie's horse be 'd'.

Let the time taken be 't'.

Distance = time * rate

Jackie's horse travelled distance; d = 28t   .....eq1

Anabel's horse travelled the distance d = 24t + 1/5.  .....eq2

Equating equation 1 and 2.

28t = 24t + 1/5

Simplifying.

4t = 1/5

t = 1/20 hour.

The same distance can be covered in 1/20 hour ;

Put the value of t in eq 1.

d = 28t

d = 28(1/20)

d = 12/5 miles

d = 1.4 miles

Thus, the miles from the starting line does which jackie's horse catch up to Anabel's is 1.4 miles.

To know more about the rate, here

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