Ask question

Ask question

All categories

3 years ago

12

What is the value of x

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

All the angles have to equal 180. If you add the two angles you get 140. You take 180 and subtract 140 and it equals to 40. The missing angle is 40 degrees.

BARSIC [14]3 years ago

4 0

The answer is 40 because all triangles add up to 180 so, 65+75+x=180

Does this help you
Pls let me be the brainliest answer

You might be interested in

To shift the graph of an equation some number of units to the __________, you

Zina [86]

Answer:

A

Step-by-step explanation:

it's A because if you're adding x from each number in the equation you would shift to the left causing the graph to become more positive but if you subtract x you would shift to the right causing the graph to become more negative.

5 0

2 years ago

Find the volume of the cone. Round your answer to the nearest tenth. Use 3.14 for n.

Luba_88 [7]

Step-by-step explanation:

use formula

volume of cone =1/3 πr²h

3 0

3 years ago

A language arts test is worth 100 points. There are a total of 26 questions. The spelling questions are worth 2 pts and vocab is

hram777 [196]

10 spelling and 16 vocab because 10 * 2 is 20 and 16 * 5 is 80 and 80+20 is 100

3 0

3 years ago

Read 2 more answers

Which expression would be easier to simplify if you used the associative property to change the grouping?

vlabodo [156]

Answer:

b

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find formula of s in terms of a, b, cos(x)

Alecsey [184]

Answer:

$\displaystyle s = \frac{2ab\cos x}{a+b}$

Step-by-step explanation:

We want to find a formula for <em>s</em> in terms of <em>a, b, </em>and cos(x).

Let the point where <em>s</em> intersects AB be D.

Notice that <em>s</em> bisects ∠C. Then by the Angle Bisector Theorem:

$\displaystyle \frac{a}{BD} = \frac{b}{AD}$

We can find BD using the Law of Cosines:

$\displaystyle BD^2 = a^2 + s^2 - 2as \cos x$

Likewise:

$\displaystyle AD^2 = b^2+ s^2 - 2bs \cos x$

From the first equation, cross-multiply:

$bBD = a AD$

And square both sides:

$b^2 BD^2 =a^2 AD^2$

Substitute:

$\displaystyle b^2 \left(a^2 + s^2 - 2as \cos x\right) = a^2 \left(b^2 + s^2 - 2bs \cos x\right)$

Distribute:

$a^2b^2 + b^2s^2 - 2ab^2 s\cos x = a^2b^2 + a^2s^2 - 2a^2 bs\cos x$

Simplify:

$b^2 s^2 - 2ab^2 s \cos x = a^2 s^2 - 2a^2 b s \cos x$

Divide both sides by <em>s </em>(<em>s</em> ≠ 0):

$b^2 s -2ab^2 \cos x = a^2 s - 2a^2 b \cos x$

Isolate <em>s: </em>

$b^2 s - a^2s = -2a^2 b \cos x + 2ab^2 \cos x$

Factor:

$\displaystyle s (b^2 - a^2) = 2ab^2 \cos x - 2a^2 b \cos x$

Therefore:

$\displaystyle s = \frac{2ab^2 \cos x - 2a^2 b \cos x}{b^2- a^2}$

Factor:

$\displaystyle s = \frac{2ab\cos x(b - a)}{(b-a)(b+a)}$

Simplify. Therefore:

$\displaystyle s = \frac{2ab\cos x}{a+b}$

5 0

3 years ago