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svlad2 [7]
1 year ago
14

A motivational speaker charges $5 for an adult's ticket and $2 for a child's ticket. For one event, he sold 785 tickets for $328

0. How many adult tickets were sold? a) 785 b) 570 c) 215 d) 58
Mathematics
1 answer:
34kurt1 year ago
5 0

Answer:

the number of adult ticket sold is 570

x=570

Explanation:

Let x represent the number of adult ticket and y represent the number of child's ticket.

Given that he charges $5 for an adult's ticket and $2 for a child's ticket.

For one event, he sold 785 tickets.

So, we have;

x+y=785\text{ -----1}

he sold 785 tickets for $3280.

Then;

5x+2y=3280\text{ ------2}

let us solve by substitution.

make y the subject of formula in equation 1 and substitute to equation 2;

y=785-x

substituting to equation 2;

\begin{gathered} 5x+2y=3280 \\ 5x+2(785-x)=3280 \\ 5x+1570-2x=3280 \\ 5x-2x=3280-1570 \\ 3x=1710 \\ x=\frac{1710}{3} \\ x=570 \end{gathered}

Therefore, since x represent the number of adult tickets sold, then the number of adult ticket sold is 570

x=570

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