All categories

3 years ago

ASAP ASAP ASAP ASAP please please help ASAP ASAP please please ASAP ASAP please ASAP help please please ASAP please

Mathematics

1 answer:

AleksandrR [38]3 years ago

6 0

Step-by-step explanation:

The lateral area is

$42\pi$

The surface area is

$60\pi$

The volume is

$63\pi$

You might be interested in

Please help with question 6

Kitty [74]

Answer:

y = -3x - 1

Use the methods on your other questions.

6 0

3 years ago

you only have to answer one, dont answer one thats been answered. also english please im a baby who wont learn new languages.

shepuryov [24]

Answer:

1. x=11

Step-by-step explanation:

2x+5=27

Subtract 5 from both sides

2x=22

Divide 2 from both sides

x=11

4 0

3 years ago

Read 2 more answers

Can someone help with this and give me an explanation on how u get im struggling

prisoha [69]

Usushahhaha shsjjiiaahhsbssbbs

6 0

3 years ago

There is a total of 25 bicycles. If the ratio of gray bicycles to black bicycles is 6 to 9, how many of them are black?

sveta [45]

the ratio is 6 to 9, 9 out of (6+9) 15 bicycles will be black.

25 * 9/15 = 15

there will be 15 black bicycles

8 0

3 years ago

Arrange the expressions in ascending order of their values when x=-2

alex41 [277]

Answer:

The expressions in ascending order would be:

$\frac{3x^2+1}{2(x-1)} < \frac{x^2-1}{1-2x} < \frac{x^2}{1-2x} < \frac{2x^2+x}{2}$

At x = -2

Explanation:

First, we will evaluate the given expressions at x = -2

1- The first expression:

$\frac{x^2}{1-2x}=\frac{(-2)^2}{1-2(-2)}=\frac{4}{5}$

2- The second expression:

$\frac{x^2-1}{1-2x}=\frac{(-2)^2-1}{1-2(-2)}=\frac{3}{5}$

3- The third expression:

$\frac{2x^2+x}{2}=\frac{2(-2)^2+(-2)}{2}=3$

4- The fourth expression:

$\frac{3x^2+1}{2(x-1)}=\frac{3(-2)^2+1}{2(-2-1)}=-\frac{13}{6}$

Then, we will arrange the values in an ascending order:

$-\frac{13}{6} < \frac{3}{5} < \frac{4}{5} < 3$

Finally, we arrange the expressions based on the value arrangement:

$\frac{3x^2+1}{2(x-1)} < \frac{x^2-1}{1-2x} < \frac{x^2}{1-2x} < \frac{2x^2+x}{2}$

Hope this helps :)

6 0

3 years ago