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xxTIMURxx [149]
1 year ago
8

In the graphic below,

Mathematics
1 answer:
sukhopar [10]1 year ago
6 0

The external angle is suplementary to the internal angle close to it. We also know that the sum of all the internal angles of the triangle are equal to 180 degrees, this means that the angle "a" is suplementary to the sum of the angles "b" and "c". Through this logic, we can conclude that since:

\begin{gathered} \angle d=180-\angle a \\ \angle b+\angle c=180-\angle a \end{gathered}

Then we can conclude that:

\angle d=\angle b+\angle c

Therefore the statement is true, the exterior angle is equal to the sum of its remote interior angles.

Let's use an example:

On this example, the external angle is 120 degrees, therefore the sum of the remote interior angles must also be equal to that. Let's try:

x=75+45=120

The sum of the remote interior angles is equal to the external angle.

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Huda made 8 matching bracelets. She used 128 beads in all. How many beads did she use per bracelet?
Elden [556K]

Answer:

To figure out the answer all you have to do is divide 128 by 8 and you get:

16 beads per bracelet


Hope this helped and plz mark as brainliest!


8 0
3 years ago
The heights in cm of some pupils are
tatuchka [14]

The median is a halfway point in the set of data.

List the numbers in order from smallest to largest:

111, 129, 144, 149, 152, 162, 166, 171

Because there are an even number of values in the data set, find the two middle numbers, add them together and then divide by 2:

Median = ( 149 + 152 ) /2

Median = 150.5

4 0
3 years ago
Which number best represents the slope of the graphed line?
ryzh [129]

Answer:

\frac{1}{2}

Step-by-step explanation:

refer to solution in the picture

3 0
3 years ago
Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe
bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W  = 100 m

The  largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES  = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter  

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W)   - L  = 2W + L

Now, fencing is given as 500 m

⇒  2W + L  = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L =  2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W  = 100 m

The maximized area = Length x Width

                                   = 200 m x 100  m = 20, 000 sq m

Hence, the  largest area that can be enclosed is 20,000 sq m.

6 0
3 years ago
Solve by factoring square roots x^2 -49=0​
aliina [53]

Answer:

X=7

Step-by-step explanation:

X = SQRT(49)

X = 7

Best regards

4 0
3 years ago
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