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2 years ago

find two consecutive intergers who sum is equal to the difference of three times the larger and two times the smaller

Mathematics

1 answer:

vekshin12 years ago

3 0

Answer:

4 and 6

Step-by-step explanation:

Let integers be x and x+2 Then:-

x + x + 2 = 3(x + 2) - 2x

2x + 2 = 3x + 6 - 2x

2x + 2 = x + 6

x = 4

The numbers are 4 and 6.

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Solve the following proportion for 17/13=9/u

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Answer:

Solution,

$\frac{17}{13} = \frac{9}{u}$

Sinplify the equation using cross multiplication

$17 \times u = 13 \times 9$

Calculate the product

$17u = 117$

Divide both sides of the equation by 17

$\frac{17u}{17} = \frac{117}{17}$

Calculate

$u = 6.88$

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Step-by-step explanation:

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A chain has 47 links. 13 link from one end is rusted. From the other end 17 link is also rusted. How many links lie between thes

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Eva8 [605]

The correct works are:

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$ .
$\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h$

<h3>Function Notation</h3>

The function is given as:

$Blue(s) = 2s^2 + 3$

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

So, we have:

$Blue(s + h) = 2(s + h)^2 + 3$

Evaluate the exponent

$Blue(s + h) = 2(s^2 + 2sh + h^2) + 3$

Expand the bracket

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$

So, the correct work is:

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$

$Blue(s) = 2s^2 + 3$

The difference quotient is represented as:

$\frac{f(x + h) - f(x)}{h}$

So, we have:

$\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}$

Evaluate the like terms

$\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}$

Evaluate the quotient

$\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h$

Hence, the correct work is:

$\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h$

Read more about function notations at:

brainly.com/question/13136492

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