find two consecutive intergers who sum is equal to the difference of three times the larger and two times the smaller
1 answer:
Answer:
4 and 6
Step-by-step explanation:
Let integers be x and x+2 Then:-
x + x + 2 = 3(x + 2) - 2x
2x + 2 = 3x + 6 - 2x
2x + 2 = x + 6
x = 4
The numbers are 4 and 6.
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