Question

Solve the equation below for x. 100 = 25e3 In4 O A. 4 B. 3 e O C. X=In4 - 3 c In100 3. In25 O D.

Answer 1

Dividing the given equation by 25 we get:

$\begin{gathered} \frac{100}{25}=\frac{25e^{3x}}{25}, \\ 4=e^{3x}\text{.} \end{gathered}$

Applying the natural logarithm to the above equation we get:

$\ln (4)=\ln (e^{3x})=3x\ln (e)=3x\text{.}$

Finally, solving for x we get:

$x=\frac{\ln (4)}{3}\text{.}$

Answer: Option A.