Advanced 2: BTS > Chapter 13 > Section Exercises 13.43 Exercise TU
1 answer:
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Answer:
(x, y) = (1, ±2)
Step-by-step explanation:
To solve this pair of equations, one can add the second equation to twice the first:
2(2x +y^2) +(3x -2y^2) = 2(6) +(-5)
4x +3x = 12 -5 . . . . simplify a bit
7x = 7 . . . . . . . . . . . collect terms
x = 1 . . . . . . . . . . . . divide by 7
Then y can be found from the first equation:
y^2 = 6 -2x = 6 -2(1) = 4
y = ±√4 = ±2
The solutions are ...
(x, y) = (1, -2) or (1, 2)
