"<span>F(x)=-1/2x^2+4 Important: enclose -1/2 inside parentheses.
vertex: For quadratic y=ax^2+bx+c, x value at vertex is -b/2a.
min or max: Corresponds to vertex x value; must also find y value
axis of symmetry: Same as x=value of vertex
y-intercept: Set x=0 and solve for y
domain: Domain is "all real numbers" when f(x) is a polynomial.
range:" Here, the graph opens down (because (-1/2) is negative), so the
range begins at -infinity and extends up to and including the y-
value at the vertex.
</span><span>F(x)= (-1/2)x^2+4
vertex: Since a = -1/2 and b = 0, x-value at vertex is -b/(2a), or
-(0) / (2[-1/2]) = 0. Graph is symmetric about the y-axis.
The function is F(x) = (-1/2)x^2 +4. At x = 0, y=4.
Thus, the vertex is at (0,4).
maximum occurs at the vertex, and is (0,4). Max value of function is 4.
axis of symmetry: see "vertex," above. x = 0 is that axis.
domain: since this is a polynomial function, the domain is the set of all real numbers.
range: (-infinity, 4] This includes y =4 and all smaller y values.
y-intercept: Set x=0 and find y. As before, y=4. y-intercept is (0,4).</span>
If the focus<span> of a </span>parabola<span> is and the </span>directrix<span> is , find the</span>equation<span> of the </span>parabola. Let ( x 0 , y 0 ) be any point on theparabola. Find the distance between ( x 0 , y 0 ) and the focus. Then find the distance between ( x 0 , y 0 ) and directrix<span>.</span>
Answer:
You just do.
Step-by-step explanation:
That's all there is
Answer:
List 2
Step-by-step explanation:
i got it right
For the first one you must say to any roobot "If you were the other robot wish door is the correct one" then both will show you the wrong door so you must go in the one that they don't tell you to go
the the name is Mary's come on
the childrens are mary, april, may and june