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12345 [234]
1 year ago
7

The probability of randomly selecting a red ball from a bag that has red, white, and green balls is 0.83 Which of the following

describes the likelihood of selecting a red ball? A. likely B. unlikely C. neither unlikely nor likely
Mathematics
1 answer:
vladimir2022 [97]1 year ago
8 0

If the probability of selecting a red ball is 0.83, which is greater than 0.5, it is likely that a red ball is selected.

Answer: letter A

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A section of road covers 18.3 square feet. Each square foot will require 5.1 minutes to repair. How many total minutes will it t
geniusboy [140]

All you have to do is multiply 18.3 x 5.1

18.3×5.1=93.33

It will take 93.33 minutes to repair the entire section. Hope that helps!

8 0
3 years ago
Read 2 more answers
Please answer this question.
Kaylis [27]
Combine the like terms
-x-x^2+7
4 0
3 years ago
For a class experiment, Danny's class weighed a log before and after subjecting it to termites. Before subjecting it to termites
m_a_m_a [10]

Answer:

4.75 pounds

Step-by-step explanation:

Before the termites: 5 pounds

After the termites: 1/4 of a pound

Amount that the termites took: x

5 - x = 1/4

Add x to both sides of the equation

5 = 1/4 + x

Subtract 1/4 from both sides of the equation

4 3/4 = x

4 3/4 = 4.75

The termites took 4.75 pounds from the log

Hope this helps :)

7 0
3 years ago
a wooden rectangular box has an area of 13 and 2/3 in the Squared. The width of the box is 1 1/3 inches. what is the length of t
Papessa [141]
The length is equal to 10 and 1/4 inches
8 0
3 years ago
a seed company has a test plot in which it is testing the germination of a hybrid seed, They plant 50 rows of 40 seeds per row.
ziro4ka [17]

Answer:

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

Step-by-step explanation:

x          P(x) x \times P(x)       x^2 \times  P(x)

33         0.02     0.66          21.78

34          0.06     2.04         69.36

35           0.1      3.5        122.5

36           0.2      7.2         259.2

37           0.24     8.88        328.56

38           0.26     9.88        375.44

39            0.1     3.9         152.1

40            0.02     0.8         32

             1        36.86      1360.9

We are supposed to find mean and standard deviation

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

7 0
3 years ago
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