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dybincka [34]
3 years ago
15

A fraction with a numerator that is greater than or equal to the denominator is 1 written in blank

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
It conveys a whole number. A fraction with a numerator that is equal to the denominator 1 - \frac{1}{1}, it clearly conveys the integer 1. And, greater than that, like \frac{7}{1}, \frac{5}{1},  \frac{10}{1}, all are whole numbers. When a fraction has a denominator of 1, it conveys the numerator as a whole number. Denominator 1 means that that there is one piece - that's whole! If there are seven pieces of wholes (\frac{7}{1}), it means there are seven wholes - an integer, which is 7.

So, the formulas can be laid as - \frac{x=1}{1}=1
And, \frac{x\ \textgreater \ 1}{1}=x
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What is the solution to the equation below log7 ANSWER FAST PLEASE
Soloha48 [4]
Log7+log(x-4)=1
Subtract log 7 from both sides
Log(x-4)=1-log7
As 1-log7 = log (10/7)
Log(x-4)=log (10/7)
As bases of logs are same.
we get
x-4=10/7
Add 4 to both sides
x=10/7 + 4
simplify
x=38/7

Answer: x=38/7

8 0
3 years ago
Pls helpppppp I really need it
Aloiza [94]

Answer:

1. 1:4 - 1/4  -  25%

2.  3:5  - 3/5 - 0.6 (simplified version)

    6:10 - 6/10 (unsimplified)

Step-by-step explanation:

5 0
3 years ago
Consider the parabola given by the equation: f(x) = 2x2 + 14.0 – 4
Softa [21]

Answer:

Step-by-step explanation:

f(x)  = 2x² + 14x - 4

= 2(x² + 7x) - 4

= 2(x² +7x + 3.5²) - 2(3.5²) - 4

= 2(x+3.5)² - 28.5

vertex (3.5, -28.5) = (7/2, -57/2)

The vertical intercept is the y-intercept, i.e., f(0) = -4.

The x-intercepts are the values of x for which y=0.

2x² + 14x - 4  = 0

x = [-14±√(14²-4(2)(-4))]/[2(2)] = [-7±√57]/2 ≅ -7.27, 0.27

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=2%20log_%7B3%7D%288%29%20%20%20-%203%20%20log_%7B3%7D%282%29%20" id="TexFormula1" title="2 log
Ghella [55]

We have:   2log₃(8) - 3log₃(2) = 2log₃(8) - log₃(2³)

= 2log₃(8) - log₃(8) =  log₃(8)

= 1,892789261 ≈ 1,9

ok done. Thank to me :>

4 0
3 years ago
Read 2 more answers
Which inequality is true
OLga [1]
The second one would be correct
7 0
3 years ago
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