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1 year ago

5. 6.9Write the decimal as a a fraction or mixed number?

Mathematics

1 answer:

salantis [7]1 year ago

5 0

6.9 as a fraction or mixed number

6.9 = 6 9/10

This is also the same as 69/10

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10 sqrt 45 please show how you did it

bulgar [2K]

$10\sqrt{45}=10\sqrt{9\cdot5}=10\sqrt{3^2\cdot5}=\\\\=10\cdot3\sqrt5=\boxed{30\sqrt5}$

6 0

3 years ago

Solve for m: E=mc² please help

aleksandr82 [10.1K]

Step-by-step explanation:

we have,

E = mc2

or, E/c2 = m

here is your answer..

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3 years ago

Solve this inequality. 8x + 6 less than or equel to 54

Step2247 [10]

Answer:

$x\le 6$

Step-by-step explanation:

We need to solve the given inequality $8x+6\le 54$ ....(1)

Subtract 6 on both sides of the equation as :

$8x+6-6\le 54-6\\\\8x\le 48$

Dividing both sides of the equation by 8 such that,

$x\le 6$

So, the value of x is less than equal to 6. Hence, this is the required solution.

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4 years ago

If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?

Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that c = $\sqrt{{a}^2 + b^{2} }$ , where c is the hypotenuse and a and b are the legs of the triangle.

So, from the problem, if c = 17 and a = 15, then, we're solving for b. So we'll rewrite the theorem to solve for b.

${c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}$

Okay, so now we have isolated the theorem for b. Let's plug in our values for c and a.

$b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8$

So, using the theorem, we found b = 8. To check our work, let's plug in b and a and solve for c.

$c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\$

So, we got our hypotenuse to equal 17 units, which is correct! So, our b is correct too. Awesome

7 0

3 years ago

You are dealt two cards successively without replacement from a standard deck of 52 playing cards. Find the probability that the

kondaur [170]

Answer:

$\frac{4}{52} \times \frac{4}{51} = \frac{16}{2652} = 0.00603 = 0.603\%$

Step-by-step explanation:

There are 52 cards in a standard deck, and there are 4 suits for each card. Therefore there are 4 twos and 4 tens.

At first we have 52 cards to choose from, and we need to get 1 of the 4 twos, therefore the probability is just

$\frac{4}{52}$

After we've chosen a two, we need to choose one of the 4 tens. But remember that we're now choosing out of a deck of just 51 cards, since one card was removed. Therefore the probability is

$\frac{4}{51}$

Now to get the total probability we need to multiply the two probabilities together

$\frac{4}{52} \times \frac{4}{51} = \frac{16}{2652} = 0.00603 = 0.603\%$

5 0

4 years ago