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vazorg [7]
1 year ago
15

A company logo

Mathematics
1 answer:
Pie1 year ago
5 0

\textit{height of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2} ~~ \begin{cases} s=sides\\[-0.5em] \hrulefill\\ s=2 \end{cases}\implies h=\cfrac{2\sqrt{3}}{2}\implies h=\sqrt{3}\implies h\approx 1.7

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Two equations are given below: a – 3b = 22 a = b – 2 What is the solution to the set of equations in the form (a, b)? (–10, –8)
aliya0001 [1]
Hi Kristian

a - 3b = 22
a = b - 2

We need to solve a = b -2 for a
First, we need to substitute b - 2 for a in a - 3b = 22
a - 3b = 22
b - 2 - 3b = 22
-2b - 2 = 22
 -2b = 22 + 2
-2b = 24
b = 24/-2
b = -12

Now substitute -12 for b in a = b - 2
a = b -2
a= -12 - 2
a= -14

Thus, the solution is a = -14 and b = -12

The correct option is the last one (-14,-12)


If you have questions about my answer, please let me know.


Good luck! 

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3 years ago
What is the factor form of x^2 y^3 -2y^3 - 2x^2 + 4?
elena-14-01-66 [18.8K]

Answer:

The chosen topic is not meant for use with this type of problem. Try the examples below.

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Step-by-step explanation:

6 0
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Answer:

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Step-by-step explanation:

All the absolute value functions given in the option are of the form:

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From your description the absolute value graph has vertex at (-4,-2)

Hence h=-4 and k=-2.

We substitute to get:

g(x)=|x--4|+-2

We simplify to get:

g(x)=|x+4|-2

6 0
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