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vazorg [7]
10 months ago
15

A company logo

Mathematics
1 answer:
Pie10 months ago
5 0

\textit{height of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2} ~~ \begin{cases} s=sides\\[-0.5em] \hrulefill\\ s=2 \end{cases}\implies h=\cfrac{2\sqrt{3}}{2}\implies h=\sqrt{3}\implies h\approx 1.7

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In □PQRS side PQ∥ side RS. If m∠P = 108degree
natka813 [3]

<h2>Given :-</h2>

In □PQRS side PQ∥ side RS. If m∠P = 108degree

and m∠R = 53degree

<h2>To Find :-</h2>

m∠Q and m∠S.

<h2>Solution :-</h2>

According to angle sum property

P∠Q=180−∠P

∠Q=180−108

\boxed{\sf{\angle Q = 72°}}

For angle S

∠S=180−∠R

∠S=180−53

\boxed{\sf {\angle S = 127°}}

\maltese\bold {lucky75} \maltese

4 0
2 years ago
Read 2 more answers
Brian, Alex &amp; Colin share some money in the ratio 1:9:3.
fiasKO [112]

Answer:

Step-by-step explanation:

1:9:3

brian gets x

alex gets 9x

colin gets 3x

Brian and colin receive 40

x + 3x = 40

x = 10

alex gets 9x = £90

3 0
2 years ago
Two teams A and B play a series of games until one team wins four games. We assume that the games are played independently and t
crimeas [40]

Answer:

4pq(p³+q³)

Step-by-step explanation:

Exactly 5 game would be when 4 wins and 1 loss of a particular person

loss has to be one of the first 4 games

A wins: qp⁴ + pqp³ + p²qp² + p³qp

= qp⁴ + qp⁴ + qp⁴ + qp⁴ = 4qp⁴

B wins: pq⁴ + qpq³ + q²pq² + q³pq

= pq⁴ + pq⁴ + pq⁴ + pq⁴ = 4pq⁴

A wins or B wins:

4pq⁴ + 4qp⁴ = 4pq(q³+p³)

6 0
3 years ago
Determine whether the relation defines y as a function of x. Give the domain.
Schach [20]

Answer:

sorry i need things to make a question

Step-by-step explanation:

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5 0
2 years ago
Heeeeeeeelpppppppppp​
Mekhanik [1.2K]

Answer:

14.83 feet

Step-by-step explanation:

c^{2} =a^{2} +b^{2}

a=\sqrt{16^{2}-6^{2}  }

a=14.83 feet

8 0
2 years ago
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