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9 months ago

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1 answer:

Pie9 months ago

5 0

$\textit{height of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2} ~~ \begin{cases} s=sides\\[-0.5em] \hrulefill\\ s=2 \end{cases}\implies h=\cfrac{2\sqrt{3}}{2}\implies h=\sqrt{3}\implies h\approx 1.7$

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In □PQRS side PQ∥ side RS. If m∠P = 108degree

natka813 [3]

<h2>Given :-</h2>

In □PQRS side PQ∥ side RS. If m∠P = 108degree

and m∠R = 53degree

m∠Q and m∠S.

<h2>Solution :-</h2>

According to angle sum property

P∠Q=180−∠P

∠Q=180−108

$\boxed{\sf{\angle Q = 72°}}$

For angle S

∠S=180−∠R

∠S=180−53

$\boxed{\sf {\angle S = 127°}}$

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4 0

2 years ago

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Brian, Alex & Colin share some money in the ratio 1:9:3.

fiasKO [112]

Answer:

Step-by-step explanation:

1:9:3

brian gets x

alex gets 9x

colin gets 3x

Brian and colin receive 40

x + 3x = 40

x = 10

alex gets 9x = £90

3 0

2 years ago

Two teams A and B play a series of games until one team wins four games. We assume that the games are played independently and t

crimeas [40]

Answer:

4pq(p³+q³)

Step-by-step explanation:

Exactly 5 game would be when 4 wins and 1 loss of a particular person

loss has to be one of the first 4 games

A wins: qp⁴ + pqp³ + p²qp² + p³qp

= qp⁴ + qp⁴ + qp⁴ + qp⁴ = 4qp⁴

B wins: pq⁴ + qpq³ + q²pq² + q³pq

= pq⁴ + pq⁴ + pq⁴ + pq⁴ = 4pq⁴

A wins or B wins:

4pq⁴ + 4qp⁴ = 4pq(q³+p³)

6 0

3 years ago

Determine whether the relation defines y as a function of x. Give the domain.

Schach [20]

Answer:

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Step-by-step explanation:

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2 years ago

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Mekhanik [1.2K]

Answer:

14.83 feet

Step-by-step explanation:

$c^{2} =a^{2} +b^{2}$

a= $\sqrt{16^{2}-6^{2} }$

a=14.83 feet

8 0

2 years ago