A. If he watered both plants on june first the next time he watered them on the same day 12 days would have passed. To find out how many days would have passed i found the lcm (lowest common multiple) by multiplying 3 and 4.
B. if he watered both plants on the same day 8 days would have passed before they where watered on the same day again. i found this answer by finding the lcm(lowest common multiple)by multiplying 2 and 4 .
Hey there, Dudedan! In a#b = a+2b, we have the first term, a, plus 2 times the second term, b. Let's try that with 3#4. 3#4 = 3+2(4) = 3 + 8 = 11. Hope this helps!
