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zvonat [6]
3 years ago
6

Evan bought two plants. He decided to water his first plant every 3 days and his second plant every 4 days. If he watered both p

lants on June 1, how many days passed before he watered both plays again
Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

A.    If he watered both plants on june first the next time he watered them on the same day 12 days would have passed. To find out how many days would have passed i found the lcm (lowest common multiple) by multiplying 3 and 4.


B. if he watered both plants on the same day 8 days would have passed before they where watered on the same day again. i found this answer by finding the lcm(lowest common multiple)by multiplying 2 and 4 .



Step-by-step explanation:


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2 years ago
the sum of three numbers is 79. The second number is 5 times the first, while the third is 16 more than the first. Find the Numb
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Let the 1st number be x; 2nd number be y; 3rd number be z.

x + y + z = 79

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Therefor,

x + (x * 5) + (x+16) = 79

1st step, multiply the 2nd number: x * 5 = 5x

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Add all like numbers:

7x + 16 = 79

To get x, transfer 16 to the other side and change its sign from positive to negative.

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To get x, divide both sides by 7

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To check. Substitute x by 9.

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3 years ago
Read 2 more answers
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