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zvonat [6]
3 years ago
6

Evan bought two plants. He decided to water his first plant every 3 days and his second plant every 4 days. If he watered both p

lants on June 1, how many days passed before he watered both plays again
Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

A.    If he watered both plants on june first the next time he watered them on the same day 12 days would have passed. To find out how many days would have passed i found the lcm (lowest common multiple) by multiplying 3 and 4.


B. if he watered both plants on the same day 8 days would have passed before they where watered on the same day again. i found this answer by finding the lcm(lowest common multiple)by multiplying 2 and 4 .



Step-by-step explanation:


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Answer:

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Part b) see the explanation

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Step-by-step explanation:

<u><em>The complete question is</em></u>

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

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In this problem we have

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Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

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For g=2 ----> a=4(2)+10=\$18

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\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]

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we have the ordered pairs

(0,10),(1,14),(2,18),(3,22),(4,26)

Plot the ordered pairs and join them to graph the line

The graph in the attached figure

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