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jasenka [17]
1 year ago
8

Fina Question 1. Write the equation of the line that goes through the points (-2,1) and (4,2)

Mathematics
1 answer:
SpyIntel [72]1 year ago
7 0

If we have two coordinates that are in the line we can find the slope with this equation:

m=\frac{y_2-y_1}{x_2-x_1}

So now we replace the coordinates so:

\begin{gathered} m=\frac{2-1}{4-(-2)} \\ m=\frac{1}{6} \end{gathered}

Now with the slope and any point we can find the intercept in the y axis by replacing x=0 so:

\begin{gathered} \frac{1}{6}=\frac{y-2}{0-4} \\ -\frac{4}{6}=y-2 \\ -\frac{2}{3}+\frac{6}{3}=y \\ \frac{4}{3}=y \end{gathered}

So the equation is:

y=\frac{1}{6}x+\frac{4}{3}

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Make R the subject<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7BP%3D10%28Q-3R%29%7D%7BR%7D" id="TexFormula1" title=" \frac
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I must assume that you meant the following:

10(Q-3R)

P = ----------------

R

Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.

Rearranging these terms so that powers of R are in descending order:

30R^2 - 10RQ + PR = 0

Factoring out R, we get

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R = 0, and 10Q - P

30R = 10Q - P, so that R = --------------

30

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Can i please get help on this?​
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yes

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where is your question?

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